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svetoff [14.1K]
3 years ago
8

In the first ten months of the year, people took out 427,113 books from the Brookton Library. The librarian would like to set a

new record and have 500,000 books go out in one year. If 38,264 books are taken out in November, how many must go out in December to meet the librarian's goal?
Mathematics
2 answers:
Jlenok [28]3 years ago
8 0

Answer:72,887

Step-by-step explanation: 500,000 - 427,113 = 72,887

solmaris [256]3 years ago
5 0

Answer:

34,623 books

Step-by-step explanation:

First, add the amount taken out in November to the amount from the first 10 months of the year.

427,113 + 38,264

= 465,377

Then, subtract this from 500,000:

500,000 - 465,377

= 34,623

So, to meet the librarian's goal, 34,623 books need to go out in December.

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Answer:

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2x − 3 x ÷ 7 x2

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Getaway Travel Agency surveyed a random sample of 454545 of their clients about their vacation plans. Of the clients surveyed, 2
mel-nik [20]

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Read 2 more answers
A ball is drawn at random from a box containing 12 red,18
Lubov Fominskaja [6]

<u>Answer:</u>

<u>For a:</u> The probability of getting a red or blue ball is 0.48

<u>For b:</u> The probability of getting a white, blue or orange ball is 0.81

<u>For c:</u> The probability of getting neither white or orange ball is 0.48

<u>Step-by-step explanation:</u>

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}     .......(1)

We are given:

Number of red balls in a box = 12

Number of white balls in a box = 18

Number of blue balls in a box = 19

Number of orange balls in a box = 15

Total balls in a box = [12 + 18 + 19 + 15] = 64

  • <u>For a:</u>

Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48

  • <u>For b:</u>

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81

  • <u>For c:</u>

Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52

Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48

7 0
3 years ago
PLS HELP ME !!!!<br> The last one is (x+2)^2 + (y-1) ^2 = 12
ladessa [460]

Answer:

its the first one or the last one

Step-by-step explanation:

i got the same thing on the graph sry

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3 years ago
Solve for x and y matrix
charle [14.2K]

Answer:

x=-1

y=5

Step-by-step explanation:

\begin{pmatrix}x&y\\ \:-1&4\end{pmatrix}\begin{pmatrix}2&5\\ \:4&1\end{pmatrix}=\begin{pmatrix}18&0\\ \:14&-1\end{pmatrix}

\begin{pmatrix}x&y\\ -1&4\end{pmatrix}\begin{pmatrix}2&5\\ 4&1\end{pmatrix}

=\begin{pmatrix}x\times \:2+y\times \:4&5x+y\\ 14&-1\end{pmatrix}

=\begin{pmatrix}18&0\\ 14&-1\end{pmatrix}

\begin{bmatrix}x\times \:2+y\times \:4=18\\ 5x+y=0\end{bmatrix}

x=-1

y=5

<u>OAmalOHopeO</u>

8 0
3 years ago
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