Answer:
The substance has a specific heat of 1.176 J/g°C
Explanation:
<u>Step 1: </u>Data given
Temperature change = 34 °C
Mass of the substance = 20 kg = 20000 grams
The substance gained 800 kJ of heat during this temperature change
<u>Step 2:</u> Calculate the specific heat
q = m*c*ΔT
⇒ with q = heat gained = 800 kJ = 800000 J
⇒ with m = the mass of the substance = 20 kg = 20000 grams
⇒ with c = the specific heat of the substance = TO BE DETERMINED
⇒ with ΔT = the change of temperature = T2 -T1 = 48° - 14 ° = 34°
c = q/(m*ΔT)
c = 800000 / (20000 * 34)
c = 1.176 J/g°C
The substance has a specific heat of 1.176 J/g°C
Answer:
Option C
Explanation:
Dipole moment being ac vector quantity has both magnitude and direction. All bonding forces have dipole moment ranging from partially positive to negative moment.
Net dipole moment is the dipole moment arising after summation of all the existing dipole moments. On the basis of dipole moment it is determined whether the molecule is polar or non polar.
Hence, option c is correct
Answer:
Yes, water can stay liquid below zero degrees Celsius. There are a few ways in which this can happen. The freezing point of water drops below zero degrees Celsius as you apply pressure. When we apply pressure to a liquid, we force the molecules to get closer together.
Explanation:
Hope this helps you. Have a nice day.^_^
Please mark as brainliest. It helps a lot:)
I think this is true because they’re in the same layer, strata which would mean they died around the same time. Hope this helps sorry if it’s wrong!