All categories

3 years ago

HALPPPPPP MEH YALL THANKSSSSSS

Chemistry

2 answers:

Nostrana [21]3 years ago

5 0

1.26 gms/cm^3 $[\frac{1 pound}{454 grams}]*[\frac{28317 cm^3}{1 ft^3}]$

numerator: (1.26 * 1 * 28317)

denominator:454 * 1 * 1

numerator/ denominator = 35679/454 = 78.59 pounds / ft^3

Ronch [10]3 years ago

4 0

Aye daddy

Lucky thing i just came back xD

Its 78.66 to the nearest sig fig

U can google it 2

Since it takes 4ever to type it out i wrote it intead srry if its messy lol

You might be interested in

Name some compounds and please amswer me guys Im from Australia and please follow bro.....Lusss

swat32

Answer:

Some common compounds in our daily lives:

Water, H2O. We need this for survival, because it serves a lot of functions in our body, such as being a medium for chemical reactions in our cells.

Carbon Dioxide, CO2. It is one of the components of air, our body also produces CO2 during respiration.

Sodium chloride, NaCl. Table salt is mostly made of sodium chloride. It is also found dissolved in sea water.

Methane, C2H4. This is a common fuel for generating electricity. It can also be found (small amounts) in air.

Nitrogen Dioxide, NO2. It can also be found in air, and it is one of the common air pollutants brought by burning of fossil fuels.

3 0

3 years ago

A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.

BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

$\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\ &=185.59\text{ g/mol} \end{aligned}$

Dimensional Analysis:

$\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }$

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0

3 years ago

4. Which of the following have mass? Select all that apply.

valkas [14]

All of these EXCEPT helium in a balloon

4 0

3 years ago

Calculate the change in pH when 71.0 mL of a 0.760 M solution of NaOH is added to 1.00 L of a solution that is 1.0O M in sodium

Eddi Din [679]

Explanation:

It is known that $pK_{a}$ value of acetic acid is 4.74. And, relation between pH and $pK_{a}$ is as follows.

pH = pK_{a} + log $\frac{[CH_{3}COOH]}{[CH_{3}COONa]}$

= 4.74 + log $\frac{1.00}{1.00}$

So, number of moles of NaOH = Volume × Molarity

= 71.0 ml × 0.760 M

= 0.05396 mol

Also, moles of $CH_{3}COOH$ = moles of $CH_{3}COONa$

= Molarity × Volume

= 1.00 M × 1.00 L

= 1.00 mol

Hence, addition of sodium acetate in NaOH will lead to the formation of acetic acid as follows.

$CH_{3}COONa + NaOH \rightarrow CH_{3}COOH$

Initial : 1.00 mol 1.00 mol

NaoH addition: 0.05396 mol

Equilibrium : (1 - 0.05396 mol) 0 (1.00 + 0.05396 mol)

= 0.94604 mol = 1.05396 mol

As, pH = pK_{a} + log $\frac{[CH_{3}COONa]}{[CH_{3}COOH]}$

= 4.74 + log $\frac{0.94604}{1.05396}$

= 4.69

Therefore, change in pH will be calculated as follows.

pH = 4.74 - 4.69

= 0.05

Thus, we can conclude that change in pH of the given solution is 0.05.

8 0

3 years ago

Ions are atoms that have gained or lost which subatomic particles?

Bad White [126]

Protons cannot be lost without the atoms becoming an entirely different element. Elements can infact have different numbers of neutrons within the same element, but neutrons are not related to the electrical charge. The answer is c. electrons.

7 0

3 years ago

Read 2 more answers