Pls answer 5a b and c for brianlist

Helpppppppppppppppppppp

a_sh-v [17]

In order going down:
5 3/5
6 5/6
4 2/3
10 1/3
11 2/3

3 0

3 years ago

Translate each sentence into a formula

Bas_tet [7]

1) Perimeter=2length+2width
This is the formula for finding the perimeter of a rectangle

2) Density=mass/volume
The “Quotient” is the answer to a division problem (like how the “sum” is the answer to an addition problem) which is why we know to divide mass and volume

3) Force = mass*acceleration
The “product” is the answer to a multiplication problem which is why we know to multiply mass and acceleration

4) surface area = 6*L^2
The formula used to calculate the area of a square is L^2. The problem tells us that surface area is the sum of all the faces of a 3D shape. Because there are 6 sides on a cube, we multiply L^2 by 6.

Hope this helps!

6 0

3 years ago

A group will equally split 3/4 pounds of a rare spice. How much spice will each person get?

Lyrx [107]

That depends on how many people are in the group!

6 0

3 years ago

Pea flowers may be purple (P) or white (p). Pea seeds may be round (R) or wrinkled (r). What proportion of the offspring from th

Rudiy27

Answer:

The proportion of the offspring from the cross PpRr × PpRr that are expected to have white flowers and wrinkled seeds is 1/16 or 6.25%.

Step-by-step explanation:

The uppercase letter represents the dominant allele, while the lowercase represents the recessive allele. The dominant allele determines the phenotype (observable trait) when it is present.

When you cross heterozygous individuals for each trait, each individual of the offspring has the probability of 1/6 of each combination of four alleles (two for each trait). Because the dominant allele determines the phenotype when it is present, the probability of dominant phenotypes is higher than recessive phenotypes.

Proportions of each phenotype in the offspring from the cross PpRr × PpRr are:

Purple flowers with round seeds: 9/16

Purple flowers with wrinkled seeds: 3/16

White flowers with round seeds: 3/16

White flowers with wrinkled seeds: 1/16

The proportion of individuals with white flowers and wrinkled seeds is the lowest because they are homozygous recessive for both traits.

8 0

3 years ago

In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposa

MakcuM [25]

Answer:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

$z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500$

$p_v =2*P(Z>0.500)=0.617$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.

Step-by-step explanation:

Data given and notation

$X_{1}=25$ represent the number of homeowners who would buy the security system

$X_{2}=9$ represent the number of renters who would buy the security system

$n_{1}=140$ sample 1

$n_{2}=60$ sample 2

$p_{1}=\frac{25}{140}=0.179$ represent the proportion of homeowners who would buy the security system

$p_{2}=\frac{9}{60}= 0.15$ represent the proportion of renters who would buy the security system

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a two sided test the p value would be:

$p_v =2*P(Z>0.500)=0.617$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.

6 0

3 years ago