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vfiekz [6]
2 years ago
6

Based on the graph below, what is the y-intercept? -5 -3 3 5

Mathematics
2 answers:
SVEN [57.7K]2 years ago
8 0

Answer:

-3

Step-by-step explanation:

A line has a point where it crosses the y-axis.

The y-axis is the vertical axis in the plane, and the point where the line intercept the y-axis is called the y-intercept.

In this case <u>we need to analyze the graph and see at what point the line and the y-axis meet</u>.

This point is -3.

because at y = -3 the line is crossing the vertical axis.

The y-intercept is -3

Crank2 years ago
7 0

The y-intercept is -3

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Suppose that 20% of students at high school A and 18% of students at high school B participate on a school athletic team. Indepe
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Answer:

B is more of a reasonable answer

Step-by-step explanation:

i  got it correct on the test

6 0
2 years ago
Calcule o determinate : <br><br> -3 2<br> 5 -3
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The answer to this question is ....................................

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3 years ago
Hey Guys!
zaharov [31]
<h3>Answer: D)  -3</h3>

Explanation:

Recall that y = f(x) since both are outputs of a function.

If k = 2, then f(x) = 2 leads to y = 2 being a horizontal line drawn through 2 on the y axis. This horizontal line only crosses the cubic curve at one spot. The same can be said if k = 0 and k = -2. So we can rule out choices A,B,C.

On the other hand, if k = -3, then f(x) = -3 has three different solutions. This is because the horizontal line through -3 on the y axis crosses the cubic at 3 different intersection points.

7 0
2 years ago
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What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?
ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

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3 years ago
Using the following diagram, tick the correct angles which are congruent to the angles given in the first column.
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Answer:

Step-by-step explanation:

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7 0
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