All categories

3 years ago

Which best describes the trends in electronegativity on the periodic table?

Chemistry

2 answers:

Serga [27]3 years ago

8 0

Answer:

On the periodic table, electronegativity generally

1. decreases as you move down a group and

2. increases as you move from left to right across a period.

Therefore, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.

Wittaler [7]3 years ago

7 0

Answer:

My bad i didnt mean to put that carry on.

Explanation:

You might be interested in

You have a 25.2 L sample of gas at 1.25 atm and 25.0 degrees Celsius. How many moles are present in this gas. For your answer, p

Elenna [48]

Answer:

<u>1.29 mol</u>

Explanation:

This is a direct application of the equation for ideal gases.

$PV=nRT$

Where:

P = pressure = 1.25 atm
V = volume = 25.2 liter
R = Universal constant of gases = 0.08206 atm-liter/K-mol
T = absolute temperature = 25.0ºC = 25 + 273.15 K = 298.15 K
n = number of moles

Solving for n:

$n=\frac{PV}{RT}$

Substituting:

$n=\frac{1.25atm\times 25.2liter}{0.08206atm-liter/K-mol\times298.15K }\\\\n=1.29mol$

8 0

3 years ago

Please help due right now <br> 10 POINTS

Darya [45]

Answer:

F=ma

Explanation:

F=m×a

according to that F÷m=a and also F ÷a=m

3 0

3 years ago

You are making a 0.2M solution of sodium acetate in the lab. Sodium acetate has a molecular mass of 82.03 g/mol. How many g of s

lyudmila [28]

Answer: The answer can be found on CHEG

Explanation:

7 0

3 years ago

The Venus flytrap is a plant that lives in wetland ecosystems that do not have nitrogen-rich soils. To make up for the lack of n

viva [34]

Canivorous plants is the correct answer for your question

6 0

3 years ago

What amount of sucrose (C12H22O11) should be added to 5.83 mol water to lower the vapor pressure of water at 50 °C to 72.0 torr?

Triss [41]

Answer:

The amount of sucrose that must be added is 1.66 moles

Explanation:

Colligative property of lowering vapor pressure has this formula:

Vapor pressure of pure solvent (P°) - Vapor pressure of solution = P° . Xm

We have both vapor pressure (pure solvent and solution9, so let's determine the ΔP

ΔP = 92.6 Torr - 72 Torr = 20.6 Torr

Let's add the data in the formula

20.6 Torr = 92.6 Torr . Xm

Xm = Mole fraction of solute → (mol of solute/ mol of solute + mol of solvent)

Mol of solvent = 5.83 mol (data from the problem)

Therefore Xm = 20.6 Torr / 92.6 Torr → 0.222

Let's find out the moles of solute (our unknown value)

0.22 = moles of solute / moles of solute + 5.83 moles of solvent

0.222 (moles of solute + 5.83 moles of solvent) = moles of solute

0.222 moles of solute + 1.29 moles of solvent = moles of solute

1.29 moles of solvent = moles of solute - 0.222 moles of solute

1.29 moles = 0.778 moles of solute

1.29 / 0.778 = moles of solute → 1.66 moles

3 0

3 years ago