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2 years ago

How many grams of O are in 905 grams of Na2O?

Chemistry

1 answer:

galben [10]2 years ago

8 0

Answer:

301.7g

Explanation:

So there's 1 out of 3 are Oxygen.

905 / 3 = 301.7

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Justification:

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How many milliliters of water are needed to prepare a 3.5M solution of NaOH if you have .5mol of the solute

Mamont248 [21]

Answer:

1335.12 mL of H2O

Explanation:

To calculate the mililiters of water that the solution needs, it is necessary to know that the volume of the solution is equal to the volume of the solute (NaOH) plus the volume of the solvent (H2O).

From the molarity formula we can first calculate the volume of the solution:

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The volume of the solution as we said previously is:

Solution volume = solute volume + solvent volume

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$MW=\frac{mass}{mol}$

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Now with the density of NaOH the milliliters of solute can be determined:

$d=\frac{mass}{volume}$

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Answer:

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How many grams of O are in 905 grams of Na2O? ​

How many grams of O are in 905 grams of Na2O?