Answer:
decreases going down within a group
Explanation:
Ionization energy of an atom is defined as the energy required to remove electron from the gaseous form the atom. The energy required to remove the highest placed electron in the gaseous form of an atom is referred to as the first ionization energy.
<em>In the periodic table, the </em><em>first ionization energy decreases down the group </em><em>because as the principal quantum number increases, the size of the orbital increases and the electron is easier to remove. </em>
<em>In addition, </em><em>the first ionization energy increases across the period </em><em>because electrons in the same principal quantum shell do not completely shield the increasing nuclear charge of the protons.</em>
An inefficient appliance costs less to operate than an efficient one, because it takes more energy to do the same job is "False".
<u>Answer:</u> Option B
<u>Explanation:</u>
Energy efficiency is about utilizing less energy consuming appliances than inefficient appliance which consume more energy to do the similar job and support for avoiding high energy bills and unnecessary pollution in the process.
The choice for energy efficiency is "ENERGY STAR LABEL" makes it known to consumers or businesses that a product, home or building is more energy efficient than others on the market.
ENERGY STAR and its partners have managed to save nearly 4 trillion kilowatt-hours of electricity from American families and businesses in 2017 and resulted into 3 billion metric tons of greenhouse gas reductions.
Answer: (a) pH = 4.774, (b) pH = 4.811 and (c) pH = 4.681
Explanation: (a) pH of the buffer solution is calculated using Handerson equation:

pKa for acetic acid is 4.76. concentration of base and acid are given as 0.95M and 0.92M. Let's plug in the values in the equation and calculate the pH of starting buffer.

pH = 4.76 + 0.014
pH = 4.774
(b) When 0.040 mol of NaOH (strong base) are added to the buffer then it reacts with 0.040 mol of acetic acid and form 0.040 mol of sodium acetate.
Original buffer volume is 1.00 L. So, the original moles of sodium acetate will be 0.95 and acetic acid will be 0.92.
moles of acetic acid after addition of NaOH = 0.92 - 0.040 = 0.88
moles of sodium acetate after addition of NaOH = 0.95 + 0.040 = 0.99
Let's again plug in the values in the Handerson equation:

pH = 4.76 + 0.051
pH = 4.811
(c) When 0.100 mol of HCl are added then it reacts with exactly 0.100 moles of sodium acetate(base) and form 0.100 moles of acetic acid(acid).
so, new moles of acetic acid = 0.92 + 0.100 = 1.02
new moles of sodium acetate = 0.95 - 0.100 = 0.85
Let's plug in the values in the equation:

pH = 4.76 - 0.079
pH = 4.681