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Rina8888 [55]
3 years ago
7

What constant do you need to add to each quadratic to complete the square?

Mathematics
1 answer:
babunello [35]3 years ago
6 0

Answer:

1. 4

2. 16

3. 9

Step-by-step explanation:

Completing the square requires a quadratic in ax^2+bx=c form. Once in this form, calculate (\frac{b}{2})^2.

1. (\frac{b}{2})^2=(\frac{-4}{2})^2=4

2. (\frac{b}{2})^2=(\frac{-8}{2})^2=16

3. Requires you divide everything by 3 first.

\frac{3x^2+18x}{3} =\frac{249}{3} \\x^2+6x=81

(\frac{b}{2})^2=(\frac{6}{2})^2=9

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You invested a total of $25000 at 3% and 4.5% simple interest. During one year, the two accounts earned $900. How much did you i
Sedaia [141]
A:amount of money invested in the account with 3% simple interest
B: amount of money invested in the account with 4.5% simple interest
a+b=25000 ——>a=25000-b

0.03a+0.045b=900
30a+45b=900000
2a+3b=60000

2(25000-b)+3b=60000
50000-2b+3b=60000
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4 0
4 years ago
Which expression is equivalent to (5x + 2) + (4x - 3)?
mamaluj [8]
The answer to this is E
7 0
3 years ago
Can I get some help on this
nordsb [41]
Answer: Choice C

The vertical asymptote at x = -4 tells us that -4 is not part of the domain. This only applies to 1/(x+4). If we plug in x = -4, we get...

f(x) = 1/(x+4)
f(-4) = 1/(-4+4)
f(-4) = 1/0
f(-4) = undefined; because of the division by zero error

The value x = -4 is allowed in the other answer choices.
5 0
3 years ago
The temperature was t°F. It fell 8°F and is now 32°F. What was the original temperature?
e-lub [12.9K]
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4 0
3 years ago
Find the gradients of line a and b
gayaneshka [121]

Answer:

Gradient of A: 2

Gradient of B: -1

Step-by-step explanation:

Gradient = change in y/change in x

✔️Gradient of A using two points on line A, (2, 5) and (0, 1):

Gradient = (1 - 5)/(0 - 2) = -4/-2

Simplify

Gradient of A = 2

✔️Gradient of B using two points on line B, (0, 5) and (5, 0):

Gradient = (0 - 5)/(5 - 0) = -5/5

Simplify

Gradient of B = -1

5 0
2 years ago
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