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IceJOKER [234]
4 years ago
10

Kyle has 2 peanuts. He eats 1. How much does he have now?

Mathematics
2 answers:
Elden [556K]4 years ago
8 0
1 peanut left its really LIKE REALLY easy one even a num skull like me can answer it........
Liula [17]4 years ago
5 0
2-1=1
hope it helped the answer is 1

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Find tan <br> A 8/15<br> B 15/8<br> C 15/7<br> D 8/17
alex41 [277]

Answer:

cos α = 8/17

Apply Pythagoras theorem for triangle ,

Let get unknown side of triangle is y

17^2 = 8^2 + y^2

17^2 - 8^2 =  y^2

225 = y^2

y = sqrt(225)

y = 15

tan α = 15/8

Step-by-step explanation:

3 0
3 years ago
1. forty thousand, two hundred sixteen in number form ?
kiruha [24]

Answer:

4,0216 Not sure abt the answer im trying my best sorry

3 0
3 years ago
Read 2 more answers
The standard deviation of a normally distributed population is 24.0. A sample of size 4 is randomly selected. The standard error
Vlad1618 [11]

The standard error of the mean is 12.

The standard error of the mean points to the standard deviation of the distribution of a sample mean obtained from a population.

The standard error S.E of the mean can be calculated by using the formula:

\mathbf{S.E = \dfrac{\sigma }{\sqrt{n}}}

where;

  • standard deviation \sigma = 24
  • sample size n = 4

\mathbf{S.E = \dfrac{24 }{\sqrt{4}}}

\mathbf{S.E = \dfrac{24 }{2}}

S.E = 12

Learn more about the Standard error of the mean here:

brainly.com/question/5327639?referrer=searchResults

3 0
3 years ago
N+4=-2 solve equation
erastovalidia [21]

Answer:

-6

Step-by-step explanation:

N+4=-2

=>N=-2-4 (subtracting 4 from both sides)

=>N=-6

plz mark me as brainliest

8 0
3 years ago
Read 2 more answers
For each equation find all the roots<br><br><br> PLEASE HELP I AM SO CONFUSED
worty [1.4K]

Answer:

Step-by-step explanation:

13.

x³-x²-x-2=0

x³-2x²+x^2-2x+x-2=0

x²(x-2)+x(x-2)+1(x-2)=0

(x-2)(x²+x+1)=0

x-2=0,x=2

x²+x+1=0

x=\frac{-1\pm\sqrt{1^2-4*1*1}}{2*1}} \\x=\frac{-1 \pm\sqrt{1-4} }{2} \\x=\frac{-1 \pm\sqrt{-3}}{2} \\x=\frac{-1\pm\sqrt{3} \iota}{2}

<em>12.</em>

<em>3x^4-11x³+15x²-9x+2=0</em>

<em>\[3x^4-3x^3-8x^3+8x²+7x²-7x-2x+2=0\]</em>

<em>3x³(x-1)-8x²(x-1)+7x(x-1)-2(x-1)=0</em>

<em>(x-1)[3x³-8x²+7x-2]=0</em>

<em>x-1=0,gives x=1</em>

<em>3x³-8x²+7x-2=0</em>

<em>3x³-3x²-5x²+5x+2x-2=0</em>

<em>3x²(x-1)-5x(x-1)+2(x-1)=0</em>

<em>(x-1)(3x²-5x+2)=0</em>

<em>x-1=0,gives x=1</em>

<em>3x²-5x+2=0</em>

<em>3x²-3x-2x+2=0</em>

<em>3x(x-1)-2(x-1)=0</em>

<em>(x-1)(3x-2)=0</em>

<em>x-1=0,gives x=1</em>

<em>3x-2=0, gives x=2/3</em>

<em>so roots are 2/3,1,1,1</em>

<em />

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3 0
2 years ago
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