Question

Mr. Ryan bought 7 tickets to an ice show and spent a total of $43. Adult tickets cost $9 and children tickets cost $4. How many tickets of each type did Mr. Ryan purchase?

Answer 1

Answer:

3 adult tickets and 4 children's tickets.

Step-by-step explanation:

what i did was 9a+4c=43 I made the list of 1-6, 2-3, 3-4, 4-3, 5-2, and 6-1. This resembles a-c. I pluged them into the equation until i got 43=43 which would be 3-4.

Answer 2

Answer:

3 adult and 4 child tickets

Step-by-step explanation:

Let a = number of adult tickets

Let c = number of child tickets

We know two things:

$a+c=7$

$9a+4c=43$

First, solve the first equation for c :

$a+c=7\\c=7-a$

Then, substitute the result into the second equation for c :

$9a+4(7-a)=43\\9a+28-4a=43\\5a+28=43\\5a=15\\a=3$

Therefore, Mr. Ryan bought 3 adult tickets and 7 – 3 = 4 child tickets.