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docker41 [41]
3 years ago
14

A rectangle has a width w that is 5 units longer than its length l. Which equation expresses the rectangle's area, A?

Mathematics
2 answers:
Ierofanga [76]3 years ago
7 0
A = L(5+L)
In order to solve the equation, you need to know the value of the length
adell [148]3 years ago
4 0

Answer: The rectangle's area is expressed as l^2+5l

Step-by-step explanation:

Since we have given that

Let the length of rectangle be 'l'.

Let the width of rectangle be 'l+5'.

We need to find the area of rectangle :

As we know the formula for "Area of rectangle ":

Area=length\times breadth\\\\Area=l(l+5)\\\\Area=l^2+5l

Hence, the rectangle's area is expressed as l^2+5l

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The length of a rectangular piece of sheet metal is 3 times it’s width. What is its length if it’s area is 192 square centimeter
weqwewe [10]

To find the missing number, you will need to divide the numbers you already have.

192 divided by 3 = 64

Your answer/length will be 64.

Area = 192

Width = 3

Length = 64

64 x 3 = 192

                                                                                Hope this helps :)

5 0
3 years ago
What is the equation of the following graph in vertex form?
VARVARA [1.3K]

Answer:

Hello,

answer B

Step-by-step explanation:

Vertex is (-3,-1)

The equation of the parabola should be:

y=k*(x+3)²-1

(0,8) is a point of the parabola:

8=k*(0+3)²-1

8+1=9k

k=1

Equation is y=(x+3)²-1

Answer B

7 0
3 years ago
Each variable indicates different weights. Which weight can you find? Find it.
SOVA2 [1]

Answer:

We can only be certain that <em>a</em> weighs 12.

There are infinitely many possiblities for <em>b</em> and <em>c</em>.

Step-by-step explanation:

We have the equation:

a+b+c+a+c+b+a+c=12+a+a+b+b+c+c+c

Each variable indicates a weight.

We would like to determine the weights of each variable (if possible).

First, we can rearrange the equation to acquire:

(a+a+a)+(b+b)+(c+c+c)=12+(a+a)+(b+b)+(c+c+c)

We can combine like terms:

3a+2b+3c=12+2a+2b+3c

Notice that both sides have 2<em>b</em> and 3<em>c</em>. Therefore, it is possible for us to cancel them since each nullify the other side. So, we will subtract 2<em>b</em> and 3<em>c</em> from both sides. This yields:

3a=12+2a

Therefore, we can solve for <em>a</em>. Subtract 2<em>a</em> from both sides:

a=12

Hence, the weight of <em>a</em> is 12.

Using the newly acquired information, we can go back to our simplified equation:

3a+2b+3c=12+2a+2b+3c

Since <em>a</em> is 12:

3(12)+2b+3c=12+2(12)+2b+3c

Evaluate:

36+2b+3c=12+24+2b+3c

Simplify:

36+2b+3c=36+2b+3c

We can subtract 36 from both sides:

2b+3c=2b+3c

As you can see, this is a true statement.

Since this is a true statement, there are infinitely many possible values for <em>b</em> and <em>c</em>.

Therefore, the only weight we are <em>certain</em> of knowing is weight <em>a</em> weighing 12.

8 0
3 years ago
Thad an Old Navy coupon for 25% off, so I went shopping for some new clothes.
creativ13 [48]

Discounted price before sales tax = 75/100 x (40 + 24 + 18 x 3) = 3/4 x (64 + 54) = 3/4 x 118 = $88.5

Total price inclusive of sales tax = 107/100 x 88.5 = $94.69

4 0
3 years ago
URGENT! PLEASE ANSWER IF YOU ACTUALLY KNOW THE ANSWER!
Zepler [3.9K]

Answer:

C. x + y = 4

Step-by-step explanation:

hard to explain sorry T-T and im really tired lolol

4 0
2 years ago
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