Question

You are given a box of 100 silver dollars, all facing heads up. You are instructed to shake the box 2 times; after the second shake, you will remove all the dollars that are heads up before shaking again. You may keep all the dollars that are still tails up following the sixth shake. How many dollars will you most likely get to keep?

Answer 1

100 divided by 2 is 50 and then divided by 6 is 8.333333 but you just round that to 8$.

Answer 2

Answer: There are 12 dollars he would most likely get to keep.

Step-by-step explanation:

Number of silver dollars = 100

Number of times box he will remove all the dollars that are head up before shaking again = 2

We need to find the number of dollars at the sixth shake.

So, Number of times he shake at the sixth shake is given by

$\frac{6}{2}=3$

So, Number of dollars he would mostly likely get to keep is given by

$Initial\times (\frac{1}{2})^3\\\\=100\times (\frac{1}{2})^3\\\\=100\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\\\\=12.5\\\\=12\ approx.$

Hence, there are 12 dollars he would most likely get to keep.