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ss7ja [257]
4 years ago
7

Simplify x4 - 81 x2 - 9

Mathematics
1 answer:
telo118 [61]4 years ago
6 0

Answer:

Step-by-step explanation:

Step by Step Solution:

More Icon

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  1 more similar replacement(s).

STEP

1

:

           x4 - 81

Simplify   ———————

           x2 - 9  

Trying to factor as a Difference of Squares:

1.1      Factoring:  x4 - 81  

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 81 is the square of 9

Check :  x4  is the square of  x2  

Factorization is :       (x2 + 9)  •  (x2 - 9)  

Polynomial Roots Calculator :

1.2    Find roots (zeroes) of :       F(x) = x2 + 9

Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  9.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,3 ,9

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        10.00      

     -3       1        -3.00        18.00      

     -9       1        -9.00        90.00      

     1       1        1.00        10.00      

     3       1        3.00        18.00      

     9       1        9.00        90.00      

Polynomial Roots Calculator found no rational roots

Trying to factor as a Difference of Squares:

1.3      Factoring:  x2 - 9  

Check : 9 is the square of 3

Check :  x2  is the square of  x1  

Factorization is :       (x + 3)  •  (x - 3)  

Trying to factor as a Difference of Squares:

1.4      Factoring:  x2 - 9  

Check : 9 is the square of 3

Check :  x2  is the square of  x1  

Factorization is :       (x + 3)  •  (x - 3)  

Canceling Out :

1.5    Cancel out  (x + 3)  which appears on both sides of the fraction line.

Canceling Out :

1.6    Cancel out  (x - 3)  which appears on both sides of the fraction line.

Final result :

 x2 + 9

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If f(x)=3/x and g(x)=3x, which of the following statements is true?
bagirrra123 [75]

Answer:

d. (g*f)(-9)=-1

Step-by-step explanation:

In this problem, we have two functions:

f(x)=\frac{3}{x}

and

g(x)=3x

The notation:

(f*g)(x) represents the composite function of f and g; this can be calculated by using the output of g(x) as input for f(x), in other words:

(f*g)(x)=f(g(x))

Simiarly, the notation (g*f)(x) can be calculated by using the output of f(x) as input for g(x), mathematically:

(g*f)(x)=g(f(x))

Using the definitions of f(x) and g(x), we can derive an expression for the two composite functions here:

(f*g)(x)=f(g(x))=\frac{3}{g(x)}=\frac{3}{3x}=\frac{1}{x}

And

(g*f)(x)=3(f(x))=3(\frac{3}{x})=\frac{9}{x}

Now we can analyze the given statements:

a. (f*g)(2)=2  --> FALSE, because (f*g)(2)=\frac{1}{2}

b. (g*f)(2)=0  --> FALSE, because (g*f)(0)=\frac{9}{0}=\infty

c.(f*g)(9)=1  --> FALSE, because (f*g)(9)=\frac{1}{9}

d. (g*f)(-9)=-1 --> TRUE, because (g*f)(-9)=\frac{9}{-9}=-1

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