Answer:
(a) J = 10560 kg-m/s (b) 251.42 N
Explanation:
Given that,
Mass, m = 4400 kg
Initial speed, u = 5.2 m/s
Final speed, v = 7.6 m/s
Time, t = 42 s
(a) Let J be the impulse exerted on the vehicle. Impuse is equal to the change in momentum such as :
J = m(v-u)
J = 4400 (7.6-5.2)
J = 10560 kg-m/s
(b) Impulse = Force × t
Hence, this is the required solution.
Longshore current brings about the transportation of sediments on the beach. Since waves usually approach the shore are an angle, the beach sand are carried up or down depending on the direction of the waves resulting in beach drift, that is, the net movement of the beach sand.
Answer:
Option D
Explanation:
<u><em>Given:</em></u>
Mass = m = 110 kg
Acceleration due to gravity = g = 9.8 m/s
<u><em>Required:</em></u>
Weight = W = ?
<u><em>Formula</em></u>
W = mg
<u><em>Solution:</em></u>
W = (110)(9.8)
W = 1078 N
Answer:
7.8% of the original volume.
Explanation:
From the given information:
Temperature = 22° C = 273 + 22 = 295° C
Pressure = 240 kPa
Temperature = 45° C
At initial temperature and pressure:
Using the ideal gas equation:
making V_1 (initial volume) the subject:
Provided the pressure maintained its rate at 240 kPa, when the temperature reached 45° C, then:
the final volume can be computed as:
Now, the change in the volume ΔV = V₂ - V₁
∴
The required fraction of the volume of air to keep up the pressure at (240) kPa can be computed as:
= 7.8% of the original volume.