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Brums [2.3K]
3 years ago
13

A man has a mass of 110 kg. What is his weight? A. 110N B. 1325 N C. 559 N D. 1078 N

Physics
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer:

Option D

Explanation:

<u><em>Given:</em></u>

Mass = m = 110 kg

Acceleration due to gravity = g = 9.8 m/s

<u><em>Required:</em></u>

Weight = W = ?

<u><em>Formula</em></u>

W = mg

<u><em>Solution:</em></u>

W = (110)(9.8)

W = 1078 N

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a) 3.14 \cdot 10^{-4} s

b) See plot attached

c) 10.0 m

d) 0.500 cm

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a)

The position of the tip of the lever at time t is described by the equation:

y(t)=(0.500 cm) sin[(2.00\cdot 10^4 s^{-1})t] (1)

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y(t)=A sin (\frac{2\pi}{T} t) (2)

where

A is the amplitude of the wave

T is the period of the wave

t is the time

By comparing (1) and (2), we see that for the wave in this problem we have

\frac{2\pi}{T}=2.00\cdot 10^4 s^{-1}

Therefore, the period is

T=\frac{2\pi}{2.00\cdot 10^4}=3.14 \cdot 10^{-4} s

b)

The sketch of the profile of the wave until t = 4T is shown in attachment.

A wave is described by a sinusoidal function: in this problem, the wave is described by a sine, therefore at t = 0 the displacement is zero, y = 0.

The wave than periodically repeats itself every period. In this sketch, we draw the wave over 4 periods, so until t = 4T.

The maximum displacement of the wave is given by the value of y when sin(...)=1, and from eq(1), we see that this is equal to

y = 0.500 cm

So, this is the maximum displacement represented in the sketch.

c)

When standing waves are produced in a string, the ends of the string act as they are nodes (points with zero displacement): therefore, the wavelength of a wave in a string is equal to twice the length of the string itself:

\lambda=2L

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\lambda is the wavelength of the wave

L is the length of the string

In this problem,

L = 5.00 m is the length of the string

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y(t)=A sin (\frac{2\pi}{T} t)

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sin(\frac{2\pi}{T}t)=1

which means that

y(t)=A

And therefore in this case,

y=0.500 cm

So, this is the displacement.

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