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Phoenix [80]
3 years ago
6

If 30ml of a fluid has a mass of 63g what is it’s density

Physics
1 answer:
murzikaleks [220]3 years ago
7 0

Answer:

The answer to your question is 2.1 g/ml

Explanation:

Data

volume = 30 ml

mass = 63 g

density = ?

Process

Density is defined as the mass per unit volume. The units of density are g/ml or kg/m³.

Formula

Density = mass / volume

Substitution

Density = 63 / 30

Result

Density = 2.1 g/ml

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A) At a certain instant, a particle-like object is acted on by a force F = (3.0 N) ihat - (3.0 N) jhat + (9.0 N) khat while the
Paha777 [63]

Answer:

a) Instantaneous rate at which the force does work on the object = -6 W

b) \texttt{Velocity of object,}\vec{v}=4\hat{j}

Explanation:

a) Given that

             \vec{F}=3\hat{i}-3\hat{j}

   and

            \vec{v}=-2\hat{i}+4\hat{k}

Instantaneous rate at which the force does work on the object is called power.

          Power is the dot product of force and velocity.

          P=\vec{F}.\vec{v}=(3\hat{i}-3\hat{j}).(-2\hat{i}+4\hat{k})=-6W

Instantaneous rate at which the force does work on the object = -6 W

b) Here given that    \vec{v}=-a\hat{j}

  Power = -12 W

  P=\vec{F}.\vec{v}=(3\hat{i}-3\hat{j}).a\hat{j}=-12W\\\\-3a=-12\\\\a=4\\\\\vec{v}=4\hat{j}

\texttt{Velocity of object,}\vec{v}=4\hat{j}

4 0
3 years ago
Which word in the sentence is a plural pronoun?
Basile [38]
(First, I guess you chose the wrong subject since this is English not Physics :p)
Now, the pronouns are words that take the place of a noun.
The Personal pronouns are: I, you, he, she, it, we, they.
I, you, he, she, it are singular; while we and they are plural.
So, in the sentence, we can clearly see the pronoun "we", which is a plural pronoun.
So the plural pronoun in this sentence is We (Answer D)

Hope this Helps! :)
5 0
3 years ago
Read 2 more answers
The part of the scientific method where we record data is the
tensa zangetsu [6.8K]
The answer is d. experiment
3 0
3 years ago
Read 2 more answers
A wire 6.90 m long with diameter of 2.15 mm has a resistance of 0.0320 Ω. Find the resistivity of the material of the wire. rho
spayn [35]
<h2>Answer:</h2>

1.68 x 10⁻⁸Ωm

<h2>Explanation:</h2>

The resistance (R) of a wire is related to its length(L), its material resistivity(ρ) and its crossectional area(A) as follows;

R = ρL/A               ------------------------(i)

Where;

A = πd² / 4              [where d = diameter of the wire]

From the question;

L = 6.90m

d = 2.15mm = 0.00215m

R = 0.0320Ω

First calculate the crossectional area (A) of the wire as follows;

A = πd² / 4      

[Take π = 3.142]

d = 0.00215m

∴ A = 3.142 x (0.00215)² / 4

∴ A = 0.000003631m²

Now, substitute the values of A, L, and R into equation (i) as follows;

R = ρL/A

0.0320 = ρ x 6.90 / 0.000003631

0.0320 = 1900302.95 x ρ

Solve for ρ;

=> ρ = 0.0320 / 1900302.95

=> ρ = 1.68 x 10⁻⁸Ωm

Therefore, the resistivity of the material of the wire is 1.68 x 10⁻⁸Ωm

4 0
3 years ago
What is the voltage across an 8.00 nm–thick membrane if the electric field strength across it is 5.50 MV/m?
polet [3.4K]

Answer:

0.044 V

Explanation:

E = Electric field = 5.5\times 10^6\ V/m

d = Thickness of membrane = 8 nm

When the electric field strength is multiplied by the membrane thickness we get the voltage

Voltage across a gap is given by

V=Ed\\\Rightarrow V=5.5\times 10^6\times 8\times 10^{-9}\\\Rightarrow V=0.044\ V

The voltage across the membrane is 0.044 V

4 0
2 years ago
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