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aniked [119]
3 years ago
13

Use the equation PiVi PfVf. Assume that Pi 101 kPa and Vi 10.0 L. If Pf 43.0 kPa, what is Vf

Physics
1 answer:
iren2701 [21]3 years ago
8 0
Solving for vf gives you PiVi/Pf. Now plug in 101kPa*10L/43kPa = 23.48L. Using significant figures i would round to 23.5L
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The period of a sound wave coming from an instrument is 0. 002 seconds. What is the frequency of the sound? Hz.
Pie

The period is the time taken by the wave to complete an oscillation. The frequency of the given sound is 500 Hz.

<h2>Period:</h2>

It is the time taken by the wave to complete an oscillation. The frequency is inversely proportional to the time:

f = \dfrac 1T

Where,

f- frequency

T - period = 0.002 s

Put the value in the equation,

f = \dfrac 1{0.002}\\\\f = 500\rm \  Hz

Therefore, the frequency of the given sound is 500 Hz.

Learn more about Period:

brainly.com/question/842349

5 0
2 years ago
On your first day at work as an electrical technician, you are asked to determine the resistance per meter of a long piece of wi
Lostsunrise [7]

Answer:

0.06\Omega/m

Explanation:

Firstly, when you measure the voltage across the battery, you get the emf,

E = 13.0 V

In order to proceed we have to assume that the voltmeter offers no loading effect, which is a valid assumption since it has a very high resistance.

Secondly, the wires must be uniform. So the resistance per unit length is constant (say z). Now, even though the ammeter has very little resistance it cannot be ignored as it must be of comparable value/magnitude when compared to the wires. This is can seen in the two cases when currents were measured. Following Ohm's law and the resistance of a length of wire being proportional to it's length, we should have gotten half the current when measuring with the 40 m wire with respect to the 20 m wire (I=\frac{V}{R}). But this is not the case.

Let the resistance of the ammeter be r

Hence, using Ohm's law we get the following 2 equations:

\frac{13}{20z+r} =7.6   .......(1)

\frac{13}{40z+r} =4.5     ......(2)

Substituting the value of r from (2) in (1), we have,

13=152z+7.6\times\frac{13-180z}{4.5}

which simplifying gives us, z=0.0589\Omega/m\approx0.06\Omega/m (which is our required solution)

putting the value of z in either (1) or (2) gives us, r = 0.5325 \Omega

3 0
3 years ago
Find the resistance of a stereo: current is 7 A voltage is 49 V.
pochemuha

Answer:

R = 7 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance. In this way, we have the following equation.

V = I*R

where:

V = voltage = 49 [V] (units of volts)

I = current = 7 [amp] (amperes)

R = resistance [ohms]

Now clearing R.

R =V/I

R = 49/7

R = 7 [amp]

5 0
3 years ago
This is how sodium appears in the periodic table. An orange box has N a at the center and 11 above. Below it says sodium and bel
Vera_Pavlovna [14]

Answer:

1 valence electrons

11 prontons

12 neutrons

Explanation:

N_{11} = 1s^{2} 2s^{2} 2p^{6} 3s^{1} \\

1 valence electrons

p = 11

11 prontons

A = p + n

A = 22,99 = 23

23 = 11 + n

n =

12 neutrons

4 0
3 years ago
Read 2 more answers
Listening to your stereo system while driving can be dangerous because:
kotegsom [21]
Hey there!

They answer is option C music would make it harder to focus on the road.

Hope this helps.
6 0
3 years ago
Read 2 more answers
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