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4 years ago

Use order of operations on [2+(9x3)]x3

Mathematics

2 answers:

jekas [21]4 years ago

7 0

Answer:

Step-by-step explanation:

We have been given an expression $[2+(9\times 3)]\times 3$ . We are asked to solve our expression using order of operations.

Order of operations: PEMDAS

P = Parenthesis

E = Exponent,

M/D = Multiplication/Division (From left to right)

A/S = Addition/Subtraction (From left to right).

First of all, we will solve within parenthesis as:

$[2+27]\times 3$

Now, we will add from left to right as:

$29\times 3$

$87$

Therefore, the solution of our given expression is 87.

lozanna [386]4 years ago

3 0

[2+(9x3)]x3
Solve for parentheses
[2+(27)]x3
Brackets are solved before the rest of the equation, but always parentheses first
[29]x3=81
The answer is 81.

Hope this helps, and hope I was the brainliest! :)

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3 years ago

Solve the initial value problem

tigry1 [53]

$9(t+1)\dfrac{\mathrm dy}{\mathrm dt}-7y=14t\implies\dfrac{\mathrm dy}{\mathrm dt}-\dfrac7{9(t+1)}y=\dfrac{14t}{9(t+1)}$

Look for an integrating factor $\mu(t)$ :

$\ln\mu=\displaystyle-\frac79\int\frac{\mathrm dt}{t+1}=-\frac79\ln(t+1)\implies\mu=(t+1)^{-7/9}$

Multiply both sides by $\mu$ :

$(t+1)^{-7/9}\dfrac{\mathrm dy}{\mathrm dt}-\dfrac79(t+1)^{-16/9}y=\dfrac{14}9t(t+1)^{-16/9}$

Condense the left side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[(t+1)^{-7/9}y\right]=\dfrac{14}9t(t+1)^{-16/9}$

Integrate both sides:

$(t+1)^{-7/9}y=\displaystyle\frac{14}9\int t(t+1)^{-16/9}\,\mathrm dt$

For the integral on the right, substitute

$u=t+1\implies t=u-1\implies\mathrm dt=\mathrm du$

$\displaystyle\int t(t+1)^{-16/9}\,\mathrm dt=\int(u-1)u^{-16/9}\,\mathrm du$

$\displaystyle=\int\left(u^{-7/9}-u^{-16/9}\right)\,\mathrm du=\frac92u^{2/9}+\frac97u^{-7/9}+C$

$\implies(t+1)^{-7/9}y=\dfrac{14}9\left(\dfrac92(t+1)^{2/9}+\dfrac97(t+1)^{-7/9}+C\right)$

$\implies(t+1)^{-7/9}y=7(t+1)^{2/9}+2(t+1)^{-7/9}+C$

$\implies y=7(t+1)+2+C(t+1)^{7/9}=7t+9+C(t+1)^{7/9}$

Given that $y(0)=12$ , we get

$12=9+C\implies C=3$

$\implies\boxed{y(t)=7t+9+3(t+1)^{7/9}}$

6 0

3 years ago

Help me fill this out thanks

irga5000 [103]

Answer:

$y = 2 \sqrt{6}$

Step-by-step explanation:

$\frac{y}{ \sin(60) } = \frac{4 \sqrt{2} }{ \sin(90) } \\ \frac{y}{ \frac{1}{2} \sqrt{3} } = \frac{4 \sqrt{2} }{1} \\ y = 4 \sqrt{2} \times \frac{1}{2} \sqrt{3} \\ y = 2 \sqrt{6}$