The perimeter of a square is 20. What is the length of one of the diagonals of the square? Show work or explain how you obtained
your answer
1 answer:
Answer:
The perimeter of a square is 20
if length of the square is x
perimeter of a square = x + x+ x + x = 4x = 20
4x = 20
x= 20/4
x = 5
Let get the length of one of the diagonal is y
According to the Pythagoras low,
y^2 = x^2 + x^2
y^2 = 5^2 + 5^2
y^2 = 25 + 25
y^2 = 50
y= sqrt(50)
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Step-by-step explanation:
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1/8 = 1/6(x)
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