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3 years ago

14

5x³+8x²-7x-6

1 answer:

Lady_Fox [76]3 years ago

5 0

Answer:

Step-by-step explanation:

Whether we divide using long division or using synthetic division, the rule is the same: If, after division, there is no remainder (i. e., the remainder is zero), the divisor binomial is a factor or the associated root is indeed a root/zero/solution.

Divide 5x³+8x²-7x-6 by (x+2) using synthetic division. Use the divisor -2 (which comes from letting x+2 = 0):

--------------------------

-2 / 5 8 -7 -6

-10 4 6

------------------------------

5 -2 -3 0 Since the remainder here is 0, we know that

-2 is a root of 5x³+8x²-7x-6 and that (x+2) is

a factor of 5x³+8x²-7x-6.

Now check out the possibility that (x+1) is a factor of 5x^3 + 8x^2 - 7x - 6:

Use -1 as the divisor in synthetic division:

--------------------------

-1 / 5 8 -7 -6

-5 -3 10

------------------------------

5 3 -10 4

Since there is a non-zero remainder (4), we can conclude that (x + 1) is NOT a factor of the given polynomial expression.

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3 years ago

120 A particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls i

seropon [69]

Answer:

a)0.5611

b)0.1828

c)0.6217

d)0.4389

e)6.25

Step-by-step explanation:

Let's define the following event :

X : ''Calls involving a fax message''

The random variable X can be modeled as a Binomial random variable.

N ~ Bi(n,p)

N ~ Bi(25,0.25)

Where n is the sample and p is the success probability

Let's also define nCr as the combinatorial number :

$nCr=\frac{n!}{r!(n-r)!}$

The probability function for X is :

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Where k is the number of success

a) $P(X\leq 6)$

$P(X\leq 6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)+P(X=6)$

$P(X\leq 6)=0.5611$

b) $P(X=6)=25C6.(0.25)^{6}.(1-0.25)^{19}=0.1828$

c) $P(X\geq 6)=1-P(X$

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In a Binomial random variable :

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3 years ago

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Leviafan [203]

Answer:

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Step-by-step explanation:

73*11= 803

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3 years ago