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3 years ago

Can you solve r=4+7x-sx for x

1 answer:

3 0

R = 4 + 7x -sx
7x - sx = r - 4
x (7 -s) = r - 4
x = r -4 / 7 - s
if we know the value of s and r, we can find the value of x.
there is another way to solve this equation:
r = 4 + 7x - sx
7x - sx = r - 4
7x - sx - (r - 4) = 0
if we put 7x - sx in plce of r - 4, we get
7x - sx - (7x - sx) = 0
7x - sx -7x +sx = 0
Now 7x- 7x = 0 and sx - sx = 0
So all the terms gives the answer 0
the solution o this equation could not be determined.

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A recent CBS News survey reported that 64% of adults felt the U.S. Treasury should continue making pennies. Suppose we select a

enyata [817]

Complete Question

A recent CBS News survey reported that 64% of adults felt the U.S. Treasury should continue making pennies. Suppose we select a sample of 18 adults.

a-1. How many of the 18 would we expect to indicate that the Treasury should continue making pennies

a-2) What is the standard deviation?

a-3) What is the likelihood that exactly 3 adults would indicate the Treasury should continue making pennies?

Answer:

a-1 $\= x = 11 .52$

a-2 $\sigma = 2.036$

a-3 $P(3) = 4.7*10^{-5}$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 18$

The proportion of adult that felt the U.S. Treasury should continue making pennies is p = 0.64

The proportion of adult that feel otherwise is

$q = 1- p = 1-0.64 = 0.36$

The mean is mathematically evaluated as

$\= x = n * p$

substituting values

$\= x = 18 * 0.64$

$\= x = 11 .52$

The standard deviation is mathematically represented as

$\sigma = \sqrt{ npq}$

substituting values

$\sigma = \sqrt{18 * 0.64 * 0.36}$

$\sigma = 2.036$

The likelihood that 3 adult would indicate the Treasury should continue making pennies is mathematically evaluated as

$P(3) = \left n} \atop \right. C_3 (p)^{3} * (q)^{n-3}$

Now

$\left n} \atop \right. C_3 = \frac{n! }{[n-3] ! 3!}$

substituting values

$\left n} \atop \right. C_3 = \frac{18! }{[15] ! 3!}$

$\left n} \atop \right. C_3 = \frac{18 * 17 * 16 * 15! }{[15] ! (3 *2 *1 )}$

$\left n} \atop \right. C_3 = \frac{18 * 17 * 16 }{ (3 *2 *1 )}$

$\left n} \atop \right. C_3 = 816$

$P(3) = 816 * (0.64 )^3 * (0.36 )^{18-3}$

$P(3) = 4.7*10^{-5}$

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<img src="https://tex.z-dn.net/?f=%20%5Clim_%7B%28x%2Cy%29%20%5Cto%20%5C%20%280%2C0%29%7D%20%28x%5E4%20%2By%5E3%29%2F%28x%5E4%20

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