Answer:
6.02 x 1023 number of atoms in one mole.
Explanation:
i cant show work because i dont want to be loud in 3 in the moring
For example:
5Cl₂ + I₂ + 12NaOH = 10NaCl + 2NaIO₃ + 6H₂O
Na₂S₂O₃ + 4I₂ + 10NaOH = 8NaI + 2Na₂SO₄ + 5H₂O
Rydberg Eqn is given as:
1/λ = R [1/n1^2 - 1/n2^2]
<span>Where λ is the wavelength of the light; 2626 nm = 2.626×10^-6 m </span>
<span>R is the Rydberg constant: R = 1.09737×10^7 m-1 </span>
<span>From Brackett series n1 = 4 </span>
<span>Hence 1/(2.626×10^-6 ) = 1.09737× 10^7 [1/4^2 – 1/n2^2] </span>
<span>Some rearranging and collecting up terms: </span>
<span>1 = (2.626×10^-6)×(1.09737× 10^7)[1/16 -1/n2^2] </span>
<span>1= 28.82[1/16 – 1/n2^2] </span>
<span>28.82/n^2 = 1.8011 – 1 = 0.8011 </span>
<span>n^2 = 28.82/0.8011 = 35.98 </span>
<span>n = √(35.98) = 6</span>
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https://www.quora.com/Why-is-fresly-prepared-FeSO4-required-for-the-ring-test
The answer is C. I hope that helps.
