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gizmo_the_mogwai [7]
3 years ago
14

How many atoms of N (nitrogen) are there in 1 mole of NH4Cl?

Chemistry
1 answer:
saw5 [17]3 years ago
6 0

Answer:

In one mole of NH₄Cl  <em>6.022 × 10²³ atoms of N </em>are present.

Explanation:

Given data:

Number of atoms of N = ?

Number of moles of NH₄Cl = 1 mol

Solution:

First we have to calculate the number of  atoms in NH₄Cl .

There is only 1 mole of N in 1 mole of NH₄Cl .

Now we will calculate the number of atoms of nitrogen in one mole of N  by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1  mole of N = 6.022 × 10²³ atoms of N

Thus in one mole of NH₄Cl  6.022 × 10²³ atoms of N are present.

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The rate constant for this zero‑order reaction is 0.0240 M ⋅ s − 1 0.0240 M·s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶products How
maw [93]

Answer: It will take for the concentration of A to decrease from 0.900 M to 0.210 M is 28.75 s

Explanation:

Zero order reaction : A reaction is said to be of zero order if the rate is independent of the concentration of the reactants, that means the rate is directly proportional to the zeroth power of the concentration of the reactants.

Expression for the zero order kinetics:

[A]=-kt+[A]_o

where [A] = concentration left after time t = 0.210 M

[A]_o = initial concentration = 0.900 M

k= rate constant =0.0240Ms^{-1}

t = time for reaction = ?

0.210=-0.0240\times t+0.900

t=28.75s

Thus it will take for the concentration of A to decrease from 0.900 M to 0.210 M is 28.75 s

7 0
3 years ago
Blink your eyes. Was work done? Explain your answer in 1 paragraph.
Zinaida [17]

Answer:

Yes work was done because it takes many muscles to blink. I didn't put it in a paragraph bc I already answered this once.

Explanation:

4 0
3 years ago
Read 2 more answers
The smallest particle of any particular type of matter is known by which of the following terms?
frez [133]
I think the correct answer is d
4 0
3 years ago
The first three terms of a sequence are given 11,22,44 find the 7th term
kvasek [131]

Answer:

The 7th term is 704

Explanation: The equation for this is a_n=11*2^n^-^1. All you have to do is substitute 7 for n and you'll get the answer.

4 0
3 years ago
How many molecules are in 28 grams of nitrogen gas in balloons?
melomori [17]

Answer:

6.022\cdot 10^{23} molecules of nitrogen gas

Explanation:

In order to convert the mass of a given compound into the number of molecules, we need to:

  • identify the number of moles of a given compound dividing its mass by the molar mass, n = \frac{m}{M},
  • multiply the number of moles by the Avogadro's constant which tells us that 1 mole contains N_A = 6.022\cdot 10^{23} molecules.

In this problem:

m_{N_2} = 28~g

M_{N_2} = 28.01~g/mol

The number of particles is then found by:

N_{N_2} = n_{N_2}\cdot N_A = \frac{m_{N_2}}{M_{N_2}} N_A = \frac{28 g}{28.01 g/mol}\cdot 6.022\cdot 10^{23} mol^{-1} = 6.022\cdot 10^{23}

6 0
3 years ago
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