Which compound(s will not form a yellow precipitate when treated with excess iodine in the presence of naoh?

1 answer:

8 0

For example:

5Cl₂ + I₂ + 12NaOH = 10NaCl + 2NaIO₃ + 6H₂O

Na₂S₂O₃ + 4I₂ + 10NaOH = 8NaI + 2Na₂SO₄ + 5H₂O

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