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Charra [1.4K]
3 years ago
13

Jessica traveled to Portland by car. Going there took 3 hours, and the return trip lasted 6 hours. Jessica averaged a speed of 4

3mph while returning. Find the average speed of the trip there
Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0

Answer:

The average speed of the trip there is <u>86 mph.</u>

Step-by-step explanation:

Given:

Time taken to reach Portland = 3 hours

Time taken to come beck from Portland = 6 hours

Average speed for the returning trip = 43 mph

Distance traveled for the returning trip can be obtained by multiplying the returning speed by returning time. Therefore, distance for returning trip is:

D=speed\times time=43\times 6=258\ miles

Now, distance traveled for the return trip is same as going to the trip.

So, distance traveled by Jessica going to Portland = 258 miles.

Time taken to go there = 3 hours

Therefore, speed of the trip there is given as the ratio of distance and time and is given as:

\textrm{Average speed}=\frac{Distance}{Time}\\\textrm{Average speed}=\frac{258}{3}=86\ mph

Therefore, the average speed of Jessica's car to go to Portland is 86 mph.

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B125%20%7D%20-%20%5Csqrt%7B180%7D%20%2B%20%5Csqrt%7B45%7D%20" id="TexFormula1" tit
Kobotan [32]

Answer:

2\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{125} = \sqrt{25(5)} = \sqrt{25} × \sqrt{5} = 5\sqrt{5}

\sqrt{180} = \sqrt{36(5)} = \sqrt{36} × \sqrt{5} = 6\sqrt{5}

\sqrt{45} = \sqrt{9(5)} = \sqrt{9} × \sqrt{5} = 3\sqrt{5}

Thus

\sqrt{125} - \sqrt{180} +\sqrt{45}

= 5\sqrt{5} - 6\sqrt{5} + 3\sqrt{5}

= 2\sqrt{5}

3 0
3 years ago
Pls help if you’re good at trigonometry tysm! Best answer is brainliest!
ExtremeBDS [4]

Answer:

7) a = 65; b = 50

8) c = 125; d = 55; e = 52

9) f = 105

Step-by-step explanation:

7)

a = 65

b + 130 = 180

b = 50

8)

c = 125

d + 125 = 180

d = 55

e = 52

9)

(180 - f) + 32 + (180 - 107) = 180

180 - f + 32 + 180 - 107 = 180

-f + 285 = 180

-f = -105

f = 105

5 0
3 years ago
Read 2 more answers
A semicircle is drawn next to the base of an isosceles triangle such that its diameter is perpendicular to the triangle's
irina1246 [14]

The total area of the semicircle and triangle is 30 + 4.5π .

The diameter of the semicircle is perpendicular to the base of the triangle.

Given diameter length = 6 cm

radius = 6 /2 = 3cm

Area of the semicircle = 1/2 πr² = 1/2π3² = 4.5π

height of the triangle = 10 cm

Area of the triangle = 1/2 × 6 × 10 =30cm

Total area of the figure = 30 + 4.5π

hence the total area of the resulting figure is 30 + 4.5π

A semicircle with one locus of points is referred to as a half-circle in mathematics, more specifically geometry. A semicircle's complete arc is always equal to 180 degrees, radians, or a half-turn.

It only contains one reflectional symmetry line. A half-disk, a twofold geometric entity that includes both the circumferential segment from one end of the arc towards the other and all the inner points, is typically referred to as a "semicircle" in non-technical language.

Disclaimer: The complete question is :

A semicircle is drawn next to the base of an isosceles triangle such that its diameter of 6 cm is perpendicular to the triangle's altitude of 10 cm

To learn more about semicircle visit:

brainly.com/question/29393120

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7 0
1 year ago
Help asp I’m on timed test
g100num [7]

Answer:

b

Step-by-step explanation:

6 0
2 years ago
Which point is in Quadrant IV?
sattari [20]

Answer:

1,1 or -1,3

Step-by-step explanation:

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3 years ago
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