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blondinia [14]
3 years ago
7

Rewrite the following equation in exponential

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

A.5^1=1

Step-by-step explanation:

512. 2. log. 5. 625 = 4. SOLUTION: ANSWER: 5. 4. = 625. Write each equation in logarithmic form. 3. 11. 3. = 1331 ... 15. SOLUTION: ANSWER: 16. 16. SOLUTION: ANSWER: 17. log. 12. 144 = 2 ... equals a little less than 2. Therefore, log. 7. 51 is the greatest. that makes A.5^1=1

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Frank and Maxine are comparing the number of boys and girls in the class. Frank says there are 12 out of a total of 24 students.
Marrrta [24]
Yes because if yuo add 12 more your adding 12 more of students to make 24

7 0
3 years ago
#14 <br> quick answer pls :)
Andrej [43]

Answer:

35.56

Step-by-step explanation:

4 0
1 year ago
Please Help !!!
solong [7]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g


Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
5 0
3 years ago
Do the following lengths form a right triangle? ​
Solnce55 [7]

Answer:

Yes, they do

Step-by-step explanation:

Because

6+8=14>9

6+9=15>8

8+9=17>6

6 0
2 years ago
Find the sum of the geometric series 40 + 40(1.005) + 40(1.005)^2 + ⋯ + 40(1.005)^11.
KiRa [710]

Answer:

The sum is 493.4

Step-by-step explanation:

In order to find the value of the sum, you have to apply the geometric series formula, which is:

\sum_{i=1}^{n} ar^{i-1} = \frac{a(1-r^{n})}{1-r}

where i is the starting point, n is the number of terms, a is the first term and r is the common ratio.

The finite geometric series converges to the expression in the right side of the equation. Therefore, you don't need to calculate all the terms. You can use the expression directly.

In this case:

a=40

b= 1.005

n=12 (because the first term is 40 and the last term is 40(1.005)^11 )

Replacing in the formula:

\frac{a(1-r^{n})}{1-r} = \frac{40(1-1.005^{12})}{1-1.005}

Solving it:

The sum is 493.4

4 0
2 years ago
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