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2 years ago

6

A mural inspired by A photographer measures 108 inches by 180 inches the scale factor is 12 what are the dimensions of the photo

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1 answer:

Papessa [141]2 years ago

8 0

108in/12 = 9 in

180 in/12 = 15 in

The dimensions of the photograh are 9 in by 15 in

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Which graph shows a line with an x-intercept of -5?

Finger [1]

Answer:

The answer is A.

Step-by-step explanation:

The only option is A. since an intercept of (-5,0)

Option B has y-int: (0,-5)
Option C has y-int: (0,5)

Option D has x-int(5,0)

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2 years ago

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3 years ago

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2 years ago

A transformation T : (x, y) → (x + 3, y + 1). Find the preimage of the point (4, 3) under the given transformation. (7, 4) (1, 2

motikmotik

Answer:

(1, 2)

Step-by-step explanation:

Remember that the final shape and position of a figure after a transformation is called the image, and the original shape and position of the figure is the pre-image.

In our case, our figure is just a point. We know that after the transformation T : (x, y) → (x + 3, y + 1), our image has coordinates (4, 3).

The transformation rule T : (x, y) → (x + 3, y + 1) means that we add 3 to the x-coordinate and add 1 to the y-coordinate of our pre-image. Now to find the pre-image of our point, we just need to reverse those operations; in other words, we will subtract 3 from the x-coordinate and subtract 1 from the y-coordinate.

So, our rule to find the pre-image of the point (4, 3) is:

T : (x, y) → (x - 3, y - 1)

We know that the x-coordinate of our image is 4 and its y-coordinate is 3.

Replacing values:

(4 - 3, 3 - 1)

(1, 2)

We can conclude that our pre-image is the point (1, 2).

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2 years ago

Jill has been watching the squirrels that live in her neighborhood. The number of squirrels changes each week. n f(n). 1 8. 2 12

qaws [65]

Answer: D) $f(n)=8(1.5)^{n-1}$

Step-by-step explanation:

From the given table we can see that this is not representing a linear function as the rate of change is not constant.

So it can be exponential growth function $A(b)^{n-1}$ , where A is the initial amount , b is the multiplicative rate of growth and n is the time period in weeks.

Now here at n=1 , f(n)=8

Therefore, A=8

Now, for n=2

$f(2)=8(b)^{2-1}\\\Rightarrow12=8b\\\Rightarrow\ b=\frac{12}{8}\\\Rightarrow\ b=1.5$

By substitute the values of A and b in the above equation, we get the equation $f(n)=8(1.5)^{n-1}$

Therefore, the function best shows the relationship between n and f(n) is

$f(n)=8(1.5)^{n-1}$ , where n is the number of weeks.

7 0

2 years ago

Read 2 more answers