Answer: Required expression:
Result: 
Step-by-step explanation:
Given phrase: 
Required expression:
['+' used to express sum, 'x' used in place of 'of']
Since 18+16 = 34
Then,
![\dfrac14\times(18+16)=\dfrac14\times34 \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}](https://tex.z-dn.net/?f=%5Cdfrac14%5Ctimes%2818%2B16%29%3D%5Cdfrac14%5Ctimes34%20%20%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes17%5C%20%5C%20%5Ctext%7B%5BDivide%20numerator%20and%20denominator%20by%202%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B17%7D%7B2%7D)
Hence,
Answer:
Jaime's. Interval not centered around the point estimate.
Step-by-step explanation:
When constructing a confidence interval based on a point estimate, the obtained point estimate must be the central value of the interval.
For Jaime's interval
Lower bound = 0.078
Upper Bound = 0.193

For Mariya's interval
Lower bound = 0.051
Upper Bound = 0.189

For a point estimate of 0.12, only Mariya's interval is adequate since Jaime's is not centered around the point estimate.
Domain: all reals, (-∝, ∝)
All inputs for x result in a solution.
It would be 7lbs, you divide the total amount by the amount per pound and you get the weight.
Considering the scale as qrst being 3/4 of defg
108x3 = 324
324/4 = 81
Area is 81 cm^2