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CaHeK987 [17]
3 years ago
13

An object goes from 14m/s to 4m/s in 10s with constant acceleration. the acceleration is?

Physics
1 answer:
forsale [732]3 years ago
8 0

a = (V - V₀) / t = (14 - 4) / 10 = 10 / 10 = 1 m/s²


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(b) During one day, 250 kg of water is pumped through
ser-zykov [4K]

Answer: The energy incident on the solar panel during that day is 9.24 \times 10^{7} J.

Explanation:

Given: Mass = 250 kg

Initial temperature = 16^{o}C

Final temperature = 38^{o}C

Specific heat capacity = 4200 J/kg^{o}C

Formula used to calculate the energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass of substance

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T_{2} = final temperature

Substitute the values into above formula as follows.

q = 250 kg \times 4200 J/kg^{o}C \times (38 - 16)^{o}C\\= 250 kg \times 4200 J/kg^{o}C \times 22^{o}C

As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.

\frac{25}{100} \times q = 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\\q = 9.24 \times 10^{7} J

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4 0
3 years ago
Slow twitch muscles are needed for?
ruslelena [56]

Speed or power activities

4 0
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Which object had more potential energy when it was lifted to a distance of 1000 centimeters? Show your calculation.
RSB [31]

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We Know That

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2. Which of the following wavelength properties would require a stopwatch to measure?
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Answer:

<u><em>A. wavelength</em></u>

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Lesechka [4]

Answer:

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as we know the relation between electric field and potential difference is given as

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\Delta V = - \int (\frac{A}{r^4}) .dr

\Delta V = \frac{A}{3r_1^3} - \frac{A}{3r_2^3}

here we know that

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so we will have

\Delta V = \frac{A}{3}(\frac{1}{1.71^3} - \frac{1}{2.89^3})

so we will have

\Delta V = 0.053 A

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3 years ago
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