Ask question

Ask question

All categories

3 years ago

15

Suppose you have two cars, and the larger one is twice as massive as the smaller one. If you and a friend push on them so that t

heir acceleration are equal, how must the forces applied to the cars compared?

1 answer:

dexar [7]3 years ago

3 0

The force on the smaller car will be less thab the large one because Force is directly proportional to mass

You might be interested in

A 3 x 10^-6 C charge is 5m away from a -2x 10^-6 C charge A. Attractive because one is positive the other one is negative B. Det

Marizza181 [45]

Answer:

0.0021576N

Explanation:

F=(k)(q1q2/r^2)

F=(8.99×10^9)(3×10^-6)(2×10^-6)/(5^2)

F=0.0021576N

5 0

2 years ago

1.The putt shot is used for hitting the golf ball off of the golf tee.

MArishka [77]

Answer:

1.True 2.

Explanation:

3 0

2 years ago

Read 2 more answers

Which evidence supports the big band theory select 3 options

ruslelena [56]

Answer:

Explanation:

There are different theories and evidence about the big bang, in this case, we're going to see three evidence.

The galaxies are moving from us, this means space is expanded, this in consequence Big Bang's explosion.

The cosmic microwave background radiation is related to the early warmth of the universe.

The observed abundance of hydrogen, helium, deuterium, lithium, these are checked from the spectra of the oldest stars.

5 0

3 years ago

Select the best reason for studying the past and its effect on us today based on "The Terror of the Middle Ages." A. to learn wh

JulijaS [17]

it is D for sure im good with history

4 0

2 years ago

Read 2 more answers

A power plant running at 39 % efficiency generates 330 MW of electric power. Part A At what rate (in MW) is heat energy exhauste

marusya05 [52]

516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.

By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river ( $Q_{out}$ ), in megawatts:

$Q_{out} = Q_{in} - W$

$Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W$ (1)

Where:

$\eta$ - Efficiency.
$W$ - Electric power, in megawatts.

If we know that $\eta = 0.39$ and $W = 330\,MW$ , then the energy rate exhausted to the river is:

$Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)$

$Q_{out} = 516.154\,MW$

516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.

We kindly to check this question on first law of thermodynamics: brainly.com/question/3808473

7 0

3 years ago