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OlgaM077 [116]
3 years ago
15

Suppose you have two cars, and the larger one is twice as massive as the smaller one. If you and a friend push on them so that t

heir acceleration are equal, how must the forces applied to the cars compared?
Physics
1 answer:
dexar [7]3 years ago
3 0
The force on the smaller car will be less thab the large one because Force is directly proportional to mass
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Kinetic energy is the energy of ______. It increases with mass ______ and _______ .Potential energy is the energy of _______or__
Alona [7]

Answer:

velocity.  height. weight. possition. place. energy. force.

Explanation: 50/50 % chance they are wrong and write.

5 0
3 years ago
If there were no external forces acting on the two pucks, their complex motion could be described as the combination of the unif
mote1985 [20]

The absence of external forces will make the pucks move in the form of a uniform circular motion.

<h3>What is a circular motion?</h3>

It should be noted that a circular motion simply means the movement of an object along the circumference of the circle.

In this case, the absence of external forces will make the pucks move in the form of a uniform circular motion.

If the friction is absent, the pucks will continue to move on the same path due to the first law of Newton and the law of conversation of energy. In this case,the results will match the predictions until there's loss in energy.

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brainly.com/question/106339

3 0
2 years ago
A student pushed a box 32.0 m across a smooth, horizontal floor using a constant force of 124 N. If the force was applied for 8.
Brilliant_brown [7]

The power developed is 500 W ( to the nearest Watt)

Power(P) is the rate at which work is done. Work done (W) is the product of the force applied on the object and the displacement (s) made by the point of application of the force.

P = \frac{W}{t}

W= F*s

Therefore,

P=\frac{F*s}{t}

Substitute the given values of force , displacement and time

F = 124 N,s = 32.0 m,t = 8.0 s

P =\frac{W*s}{t} =\frac{124N*22.0s}{8.0s} =496 W

Thus the Power can be rounded off to the nearest value of 500 W

3 0
3 years ago
Read 2 more answers
A 0.5 kg stone is raised from 1m to 2m height from the ground. what is the change in potential energy of the stone?
Usimov [2.4K]

Given: The mass of stone (m) = 0.5 kg

Raised from heights (h₁) = 1.0 m to (h₂) = 2.0 m

Acceleration due to gravity (g) = 9.8 m/s²

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where, all alphabets are in their usual meanings.

Now, we shall calculate the change in potential energy of the stone

Δ P = P₂ - P₁ = mg (h₂ - h₁)

or,                = 0.5 kg ×9.8 m/s² ×(2.0 m - 1.0 m)

or,                = 4.9 J

Hence, the required change in the potential energy of the stone will be 4.9 J

4 0
3 years ago
Discuss why Wolpert says we have a brain.
ycow [4]

Answer:

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8 0
2 years ago
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