Ask question

Ask question

All categories

3 years ago

12

The electric field in a certain region of Earth’s atmo- sphere is directed vertically down. At an altitude of 300 m the field ha

s magnitude 60.0 N/C; at an altitude of 200 m, the magnitude is 100 N/C. Find the net amount of charge contained in a cube 100 m on edge, with horizontal faces at altitudes of 200 and 300 m

2 answers:

I am Lyosha [343]3 years ago

6 0

Answer:

Net charge contained in the cubeq= 3.536×10^-6C

Explanation:

Formular for total flux in a cube is given as:

Total flux= E300Acos(180) + E200Acos(0)

Where A is crossectional area

Total flux= A(E200-E300)

Total flux= q/Eo

q= Eo×total flux

q=(8.84×10^-12)×(100)^2×(100-60)

q= 3.536×10^-6C

Alisiya [41]3 years ago

3 0

Answer:

$q = 3.54*10^{-6}C$

Explanation:

Given that:

A = 100m

( $E_l$ ) = 100

( $E_v$ ) = 60

E₀(constant) = 8.85 * 10⁻¹²

The net amount of charge can be found using the expression:

= $\frac{q}{E_0} = \theta$

= $q= \theta E_0$ where θ =0; A(El-Ev)

= $q= E_0A(E_l-E_v)$

= $q=(8.85*10^{-12}*(100)^2*(100-60)$

= $q=(8.85*10^{-12}*(100)^2*(40)$

= $q=(8.85*10^{-12}*(400,000)$

= $q = 3.54*10^{-6}C$

You might be interested in

Difference between universal law of gravitation and acceleration due to gravity

marishachu [46]

Explanation:

The acceleration on an object due to the gravity of any massive body is represented by g (small g). The force of attraction between any two unit masses separated by unit distance is called universal gravitational constant denoted by G(capital g). The relation between G and g is not proportional. That means they are independent entities.

G and g

In physics, G and g can be related mathematically as –

\(g=\frac{GM}{R^{2}}\)

Where,

1=g is the acceleration due to the gravity of any massive body measured in m/s2.

2=G is the universal gravitational constant measured in Nm2/kg2.

3=R is the radius of the massive body measured in km.

4=M is the mass of the massive body measured in Kg.

7 0

3 years ago

An object, 5 cm high, is placed on the principal axis of a diverging lens of focal length 20 cm. The object is 30 cm from the le

Nata [24]

Answer:

The answer is 70 cm

Explanation:

If you add All the numbers together, you receive an 55 cm then you add 15 because the points on the diagram also count.

3 0

2 years ago

A 4.76 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en

Romashka-Z-Leto [24]

Answer:

The magnitude of the force is 64.634 newtons.

Explanation:

According to the statement, the crate is a constant mass system, whose upward force is described by the following expression:

$F(t) = m\cdot \ddot{y} (t)$ (1)

Where:

$F(t)$ - Force, in newtons.

$m$ - Mass, in kilograms.

$\ddot {y}(t)$ - Acceleration, in meters per square second.

The function acceleration is obtained by deriving the function position twice in time:

$\dot y (t) = 2.80 + 1.83\cdot t^{2}$ (2)

$\ddot y(t) = 3.66\cdot t$ (3)

And we expand (1) by applying (3):

$F(t) = 3.66\cdot m \cdot t$

Where $t$ is the time, in seconds.

If we know that $m = 4.76\,kg$ and $t = 3.71\,s$ , then the magnitude of the force is:

$F = 3.66\cdot (4.76)\cdot (3.71)$

$F = 64.634\,N$

The magnitude of the force is 64.634 newtons.

6 0

3 years ago

A point source at the origin emits sound of frequency 175 Hz uniformly in all directions. On the x-axis at x=100 m, the sound in

hammer [34]

Answer:

Multiple answers:

1. Power output P=17.59W

2.Intensity 160m I=17.6W/ $m^{2}$

3. dB = 77.3

4. f=178.5 Hz

Explanation:

First one comes from the expression

$I=\frac{P}{4\pi r^{2} }$

where<em> I </em>is the intensity, <em>P </em>is the power and <em>r </em>is the radio of the spherical wave, or in this case, the distance <em>x</em>. I solved for the Power by multiplying Intensity with the area (4 $\pi x^{2}$

Second one is done with:

$\frac{I_{2} }{I_{1} } =\frac{x^{2}_{1} }{x^{2} _{2}}$

Solving for Intensity 2, the result mentioned.

The third is simply computed with

$dB=10*log\frac{I}{10^{-12} }$

And finally the last one is done with doppler effect, taking into account the speed of the air as in 10ºC 337m/s.

$f=f_{initial} *(\frac{s+v_{receiver} }{s+v_{source} } )$

Where <em>Finitial</em> is the frequency emitted and <em>s</em> is the speed of the sound. The wind blowing in positive is, in principle, going away of the observer.

8 0

3 years ago

How do scientists determine where an earthquake starts?

azamat

Scientists use a method called triangulation to determine where the earthquake was. It is called triangulation because a triangle has three sides, and it takes three seismographs to locate an earthquake.

5 0

3 years ago

Read 2 more answers