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katen-ka-za [31]
2 years ago
6

a rectangular tank measures 12.5 metres long 10.0 wide and 2.0 metre high calculate the mass of the water in the tank when it is

full the density of water 1000 kg per metre cube assume the measurement are internal​
Physics
1 answer:
Tom [10]2 years ago
7 0

Answer:

250000kg

Explanation:

Mass =density * volume

Density=1000kg/m³

Volume=l*w*h

12.5*10.0*2.0=250m³

Mass=1000 *250

=250000kg

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A compressed spring does not have elastic potential energy.
Alexus [3.1K]

Answer:

False

Explanation:

The second you let go its gonna release kinetic energy that's why it's potential

6 0
2 years ago
The Outlaw Run roller coaster in Branson, Missouri, features a track that is inclined at 84 ∘ below the horizontal and that span
harina [27]

Answer:

Explanation:

a)

Ff = μmgcosθ

Ff = 0.28(1600)(9.8)cos(-84)

Ff = 458.9217...

Ff = 460 N

b)  ignoring the curves required at top and bottom which change the friction force significantly, especially at the bottom where centripetal acceleration will greatly increase normal forces and thus friction force.

W = Ffd

W = 458.9217(-49.4/sin(-84)

W = 22,795.6119...

W = 23 kJ

c) same assumptions as part b

The change in potential energy minus the work of friction will be kinetic energy.

KE = PE - W

½mv² = mgh - (μmgcosθ)d

v² = 2(gh - (μgcosθ)(h/sinθ))

v = √(2gh(1 - μcotθ))

v = √(2(9.8)(49.4)(1 - 0.28cot84))

v = 30.6552...

v = 31 m/s

5 0
2 years ago
17. The four points built into the camera to ensure that each exposure can be oriented
3241004551 [841]
The diameter of the circle is 18 m. Eugene incorrectly says that the circumference of the circle is about 113.04 m. What mistake did Eugene make? Use 3.14 for pi.
7 0
3 years ago
A circular loop of wire of area 10 cm^2 carries a current of 25 A. At a particular instant, the loop lies in the xy-plane and is
S_A_V [24]

The magnetic dipole moment of the current loop is  0.025 Am².

The magnetic torque on the loop is 2.5 x 10⁻⁴  Nm.

<h3>What is magnetic dipole moment?</h3>

The magnetic dipole moment of an object, is the measure of the object's tendency to align with a magnetic field.

Mathematically, magnetic dipole moment is given as;

μ = NIA

where;

  • N is number of turns of the loop
  • A is the area of the loop
  • I is the current flowing in the loop

μ = (1) x (25 A) x (0.001 m²)

μ = 0.025 Am²

The magnetic torque on the loop is calculated as follows;

τ = μB

where;

  • B is magnetic field strength

B = √(0.002² + 0.006² + 0.008²)

B = 0.01 T

τ = μB

τ =  0.025 Am² x 0.01 T

τ = 2.5 x 10⁻⁴  Nm

Thus, the magnetic dipole moment of the current loop is determined from the current and area of the loop while the magnetic torque on the loop is determined from the magnetic dipole moment.

Learn more about magnetic dipole moment here: brainly.com/question/13068184

#SPJ1

8 0
1 year ago
A 15.0 m long steel rod expands when its temperature rises from 34.0 degrees C to 50.0 degrees C. What is the change in the beam
azamat
0.00288................
8 0
3 years ago
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