Ask question

Ask question

All categories

katen-ka-za [31]

3 years ago

6

a rectangular tank measures 12.5 metres long 10.0 wide and 2.0 metre high calculate the mass of the water in the tank when it is

full the density of water 1000 kg per metre cube assume the measurement are internal

1 answer:

Tom [10]3 years ago

7 0

Answer:

250000kg

Explanation:

Mass =density * volume

Density=1000kg/m³

Volume=l*w*h

12.5*10.0*2.0=250m³

Mass=1000 *250

=250000kg

You might be interested in

The current supplied by a battery as a function of time is I(t) = (0.88 A) e^(-t*6 hr). What is the total number of electrons tr

Nimfa-mama [501]

Answer:

$N = 1.2 \times 10^{23}$

Explanation:

As we know that the current through the battery is given as

$i = (0.88 A) e^{-t/6}$

here from above equation we know that current will become zero when time elapsed is very large

so here we can say that charge will flow through the battery from t = 0 to t = infinite

now we have

$q = \int i dt$

$q = \int (0.88 A) e^{-t/6} dt$

$q = 0.88\times -6(3600)\times (e^{-t/6})$

$q = -1.90 \times 10^{4} (0 - 1)$

$q = 1.90 \times 10^{4} C$

As we know that

$q = Ne$

$N = \frac{q}{e}$

$N = \frac{1.90 \times 10^4}{1.6 \times 10^{-19}}$

$N = 1.2 \times 10^{23}$

4 0

3 years ago

A long solenoid (diameter = 5.0 cm) is wound with 960 turns per meter of thin wire through which a current of 300 mA is maintain

Semenov [28]

Answer: The magnetic field B= 4.82×10^-4T

Explanation:

There are two sources of magnetic field; the magnetic field due to solenoid and magnetic field due to wire. Their sum will give the total magnetic field

The magnetic field due to solenoid is constant at any point while the magnetic field due to wire varies with 1/radius.

Since they are perpendicular to each other;

Using Pythagoras theorem

B^2 =(B1)^2+B2)^2

B1 is the magnetic field due to solenoid and B2 is the magnetic field due to wire

B1= (μNI1)/L

B2=μI2/2πr

Where N/L is the of turns per meter = 960m^-1

I1 is the current in the solenoid =300mA=0.3A

I2 is the current in the wire = 12A

r is the distance from the axis of solenoid = 2cm= 0.02m

μ is the magnetic constant= 4π×10^-7Tm/A

Magnetic field due to solenoid B1=(4π×10^-7×960×0.3)

B1= (3.6191×10^-4 )

Magnetic field due to wire

B2 = (4π×10^-7×12)/2π × 0.02

B2 = 1.2×10^-4

B^2 =( 3.16191×10^-4)^2 × (1.2×10^-4)^2

B=3.8×10^-4T

Therefore the magnetic field is 0.38mT

5 0

3 years ago

A ball is thrown with an initial upward velocity of 5 m/s.

miv72 [106K]

Answer:

A ball is thrown at an initial height of 5 feet with an initial upward velocity at 29 ft/s. lets assume that balls height h (in feet) after t seconds is give by:

<u>h= 5 + 29t -16t^2</u>

Explanation:

h= 5 + 29t -16t^2

a time when the ball's height will be 17 ft

17 = 5 + 29t -16t2

0 = -17 + 5 + 29t -16t2

0 = -12 + 29t - 16t2

Using the quadratic equation:

t = (-29±√(292-(4*(-16)*(-12))))÷2(-16)

= (-29±√(841 - 768))÷(-32)

= (-29±√(73))÷(-32)

= (-29 + 8.544)÷(-32) or (-29 - 8.544)÷(-32)

= (-20.456)÷(-32) or -37.544÷(-32)

= 0.64 or 1.17

So, the ball is at a height of 17 ft twice: once on the way up after 0.64 seconds and once on the way back down after 1.17 seconds.

6 0

4 years ago

Need help on question b

ZanzabumX [31]

The answer is A.

A positive charge’s electric field pushes out.

Hope this helps! -Avenging

8 0

3 years ago

suggest a Form of renewable energy that could be used to power an electric ticket machine that only needs to work during dayligh

Stella [2.4K]

Answer:

Solar Energy

Explanation:

5 0

4 years ago