Ask question

Ask question

All categories

katen-ka-za [31]

3 years ago

6

a rectangular tank measures 12.5 metres long 10.0 wide and 2.0 metre high calculate the mass of the water in the tank when it is

full the density of water 1000 kg per metre cube assume the measurement are internal

1 answer:

Tom [10]3 years ago

7 0

Answer:

250000kg

Explanation:

Mass =density * volume

Density=1000kg/m³

Volume=l*w*h

12.5*10.0*2.0=250m³

Mass=1000 *250

=250000kg

You might be interested in

Weigt A box sitting still on the ground by itself has a weight of 700N, what is the mass? (gravity's acceleration is 9.80 m/s2)

Alex

Force=700N
Acceleration=9.8m/s^2

Using newtons law

$\\ \rm\longmapsto F=ma$

$\\ \rm\longmapsto m=\dfrac{F}{a}$

$\\ \rm\longmapsto m=\dfrac{700}{9.8}$

$\\ \rm\longmapsto m=71.4kg$

7 0

3 years ago

Pls help my science teacher is a horrible teacher...

Anettt [7]

First of all, looks like your teacher is indeed pretty horrible. Secondly, the constraints to consider would be proper weight distribution, methods to minimize excessive motion of the building structure, and quantities such as volume and density, which would help in determining the optimal structure. Keeping the frequency of oscillation for a building low in case of an earthquake or natural disaster would also be a priority.

4 0

3 years ago

Which will a positively charged objects attract

Vitek1552 [10]

Me and you! enjoy your day girllllaa or boy

6 0

3 years ago

Read 2 more answers

A ball is dropped from rest at the top of a 6.10 m

natita [175]

Answer:

n = 5 approx

Explanation:

If v be the velocity before the contact with the ground and v₁ be the velocity of bouncing back

$\frac{v_1}{v}$ = e ( coefficient of restitution ) = $\frac{1}{\sqrt{10} }$

and

$\frac{v_1}{v} = \sqrt{\frac{h_1}{6.1} }$

h₁ is height up-to which the ball bounces back after first bounce.

From the two equations we can write that

$e = \sqrt{\frac{h_1}{6.1} }$

$e = \sqrt{\frac{h_2}{h_1} }$

So on

$e^n = \sqrt{\frac{h_1}{6.1} }\times \sqrt{\frac{h_2}{h_1} }\times... \sqrt{\frac{h_n}{h_{n-1} }$

$(\frac{1}{\sqrt{10} })^n=\frac{2.38}{6.1}$ = .00396

Taking log on both sides

- n / 2 = log .00396

n / 2 = 2.4

n = 5 approx

3 0

3 years ago

Perfect square of 11650

suter [353]

Answer:

Since the area of the perfect square is 11650, and all of a squares sides ar equal, we just need to find the square root.

The square root of 11650 is 107.935166.

One side of the square is 107.935166

107.935166 x 107.935166 = 11650

(っ◔◡◔)っ ♥ Hope It Helps ♥

7 0

3 years ago

Read 2 more answers