1. The half-life of the element is 22 years
2. The time taken for 308 g of the sample to decay to 4.8125 g is 132 years
<h3>Definition of half-life </h3>
Half-life is simply defined as the time taken for half of a material to decay.
<h3>1. How to determine the half-life </h3>
- Original amount (N₀) = 45 g
- Half of the original amount = 45 / 2 = 22.5 g
From the diagram, the time for 22.5 g is 22 years.
Thus, the half-life of the element is 22 years
<h3>2. How to determine the time </h3><h3>i. Determination of the number of half-lives </h3>
- Original amount (N₀) = 308 g
- Amount remaining (N) = 4.8125 g
- Number of half-lives (n) =?
2ⁿ = N₀ / N
2ⁿ = 308 / 4.8125
2ⁿ = 64
2ⁿ = 2⁶
n = 6
<h3>ii. Determination of the time </h3>
- Number of half-lives (n) = 6
- Half-life (t½) = 22 years
t = n × t½
t = 6 × 22
t = 132 years
See attached photo for diagram
Learn more about half life:
brainly.com/question/26374513
<u>Given:</u>
Mass of asteroid, M1 = 5.00*10¹² kg
Velocity of asteroid V1 = 15.0 km/s
Mass of moon, M2 = 7.36*10²² kg
<u>To determine:</u>
The recoil velocity of moon, V2
<u>Explanation:</u>
Since the collision is perfectly inelastic, momentum is conserved. therefore,
M1 * V1 = M2* V2
V2 = M1*V1/M2 = 5.00*10¹² *15.0 /7.36*10²² = 1.02*10⁻⁹ km/s
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Answer:
Theanswer to your question is:
Limiting reactant = FeCl₃
Excess reactant = 1.66 g of Mg
Explanation:
Data
Mg = 41 g = 24.31 g/mol
FeCl₃ = 175 g = 162.2 g/mol
3Mg(s) + 2FeCl₃(s) → 3MgCl₂(s) + 2Fe(s)
3(24.31) of Mg ------------------ 2(162.2) of FeCl₃
72.93 g of Mg ------------------ 324.4 g of FeCl₃
Theoretical Proportion = 324.4/72.93 = 4.44
Practical proportion = 175 / 41 = 4.2
As the proportion disminishes the limiting reactant is FeCl₃.
Excess reactant
72.93 g of Mg ------------------ 324.4 g of FeCl₃
x ------------------------- 175 g of FeCl₃
x = (175 x 72.93) / 324.4
x = 39.34 g of Mg
Excess = 41 - 39.34
= 1.66 g of Mg
