Solving the inequality
the value of q is ![q\leq 6](https://tex.z-dn.net/?f=q%5Cleq%206)
Step-by-step explanation:
We need to solve the inequality:
and find value of q
Solving:
![-3q+12\geq 4q-30\\Adding\,\,-12\,\,on\,\,both\,\,sides:\\-3q+12-12\geq 4q-30-12\\-3q\geq 4q-42\\Adding\,\,-4q\,\,on\,\,both\,\,sides:\\-3q-4q\geq 4q-42-4q\\-7q\geq -42\\Divide\,\,both\,\,sides\,\,by\,\,7\\\frac{-7q}{7}\geq \frac{-42}{7}\\ -q\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1\,\,and\,\,reverse\,\,the\,\,inequality:\\q\leq 6](https://tex.z-dn.net/?f=-3q%2B12%5Cgeq%204q-30%5C%5CAdding%5C%2C%5C%2C-12%5C%2C%5C%2Con%5C%2C%5C%2Cboth%5C%2C%5C%2Csides%3A%5C%5C-3q%2B12-12%5Cgeq%204q-30-12%5C%5C-3q%5Cgeq%204q-42%5C%5CAdding%5C%2C%5C%2C-4q%5C%2C%5C%2Con%5C%2C%5C%2Cboth%5C%2C%5C%2Csides%3A%5C%5C-3q-4q%5Cgeq%204q-42-4q%5C%5C-7q%5Cgeq%20-42%5C%5CDivide%5C%2C%5C%2Cboth%5C%2C%5C%2Csides%5C%2C%5C%2Cby%5C%2C%5C%2C7%5C%5C%5Cfrac%7B-7q%7D%7B7%7D%5Cgeq%20%5Cfrac%7B-42%7D%7B7%7D%5C%5C%20-q%5Cgeq%20-6%5C%5CMultiply%5C%2C%5C%2Cboth%5C%2C%5C%2Csides%5C%2C%5C%2Cby%5C%2C%5C%2C-1%5C%2C%5C%2Cand%5C%2C%5C%2Creverse%5C%2C%5C%2Cthe%5C%2C%5C%2Cinequality%3A%5C%5Cq%5Cleq%206)
So, solving the inequality
the value of q is ![q\leq 6](https://tex.z-dn.net/?f=q%5Cleq%206)
Keywords: Solving inequality
Learn more about solving inequality at:
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Answer:
idk
Step-by-step explanation:
Answer:
The correct answer is B.
Step-by-step explanation:
Multiply the first equation by -7, and the second equation by 8, and then add.
What you're trying to do is cancel them out so they have to opposite signs in order for them to cancel out. You can't do that if the signs are the same, which is what option A suggests doing. B is the correct answer.