√z = 13 - 8
√z = 5
z = 5²
z = 25
In this case the z can be any number, however z cannot be less than 0 and that is the restriction. (for example; √-1 = irrational number, cannot be solved.)
Answer:
4c + 15
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW;
A department store's customer parking lot has 4 rows with an equal number of parking spots in each row. The lot also has 15 parking spots for store employees. If c cars can be parked in each of the 4 main rows of the parking lot, what is the expression for the maximum number of cars that can be parked in the parking lot?
15c − 4
c(15 − 4)
4c + 15
4(c + 15)
✓We were told that the customer stores parking has Total number of 4 rows,
✓ for " c" cars to be parked in the 4 main rows i.e in each of them, we can calculate the overall numbers of car parked in the rolls as ( 4 × c)= 4c
✓ we were told that there are 15 parking spots available to employees in the store
✓ maximum number of cars that can fit into the parking lot will be ( 15 + 4c)
= 4c + 15
Answer:
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this is not that long but I tried
<span>Vcube = Ledge^3
8000cm^3 = Ledge^3
use the cube root of each side and you have the measure of an edge in cm.
8000^(1/3) = 20
every edge is 20 cm
20^2 = 400
The area of each face is 400 cm^2. </span>
Answer:
187
Step-by-step explanation: