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NikAS [45]
3 years ago
5

There are 18 pieces of chalk. The ratio if chalk that is yellow to chalk that is not yellow is 1:2. How many more pieces of whit

e chalk are there?
Mathematics
1 answer:
katen-ka-za [31]3 years ago
5 0
The amount of chalk are equal
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Write the standard form and word form for the decimal represented by 700+40+0.6+0.08+0.006. what is the relationship between the
eduard

In standard form, it is expressed as 7.407 * 10^2 while he relationship between the values of the two 6s is that 0.6 is to the nearest tenth and 0.006 is to nearest thousandth

<h3>Expressing decimals in standard form</h3>

The standard form of an equation is expressed as A * 10^n

where

A is any number between 1 and 10

n is any integer

Given the sum below;

700+40+0.6+0.08+0.006.

Take the sum of the expression

740 +0.6 + 0.08 + 0.006

740.686

In standard form, it is expressed as 7.407 * 10^2 while he relationship between the values of the two 6s is that 0.6 is to the nearest tenth and 0.006 is to nearest thousandth

Learn more on standard form here: brainly.com/question/525947

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What expression is equivalent to -21? <br> A. 9-(-12)<br> B. 9+(-12)<br> C. -9+12<br> D. -9-12
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Step-by-step explanation:

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Consider the function f(x)=x+9−−−−−√−3f(x)=x+9−3 on the domain [−9,[infinity])[−9,[infinity]). The inverse of this function is f
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Answer with Step-by-step explanation:

We are given that a function f(x)=\sqrt{x+9}-3

Domain of f(x)=[-9,\infty)

The inverse of given function f^{-1}(x)=x^2+6x

a.We have to find the domain of f^{-1}(x)

We know that domain of f(x) is convert into range of f^{-1}(x) and range of f(x) is convert into domain of f^{-1}(x)

If we substitute x=-9 in the given function then we get

f(x)=\sqrt{-9+9}-3=-3

Therefore, range of f(x) =[-3,\infty)

Domain of f^{-1}(x)=[-3,[tex]\infty)

b.Range  of f(x) is restricted .Therefore, domain of f^{-1}(x) must be restricted because range of f(x) is converted into domain of f^{-1}(x) and range of f(x) is restricted.

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