Answer:
=5880b2x4−6048bcx4+1512c2x4−3920b2x3+4032bcx3−1008c2x3+33320b2x2−34272bcx2+8568c2x2−82320b2x+84672bcx−21168c2x−31360b2+32256bc−8064c2+6x2+6x−24
Step-by-step explanation:
$ 6,650 was invested at 3.5%, and $ 5,950 at 4.5%.
Since a student takes out two loans to help pay for college expenses, and the total amount of money borrowed is $ 12600, and both loans have interest that accrues annually, and the first loan has an interest rate of 3.5%, and the second loan has an interest rate of 4.5%, and after the first year, the interest from both loans total $ 500.5, to find the initial amount borrowed at 3.5% the following calculation must be performed:
- 6300 x 0.035 + 6300 x 0.045 = 504
- 6600 x 0.035 + 6000 x 0.045 = 501
- 6700 x 0.035 + 5900 x 0.045 = 500
- 6650 x 0.035 + 5950 x 0.045 = 500.5
Therefore, $ 6,650 was invested at 3.5%, and $ 5,950 at 4.5%.
Learn more about interest in brainly.com/question/25831522
Answer:
Step-by-step explanation:
99x - 44y = -605
-99x + 63y = 738
19y = 133
y = 7
-9x + 28 = 55
-9x = 27
x = -3
(-3, 7)
5x-2y=-10
Making y the subject of the formula;
5x+10=2y
2y=5x+10
y=
![\frac{5}{2} x+5](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B2%7D%20x%2B5)
The slope is 2.5 or five halves
I beleive it is A or B if I had to choose I'd go with A