Which of the graphs below correctly solve for x in the equation −x2 + 5x + 6 = 3x − 2? Graph of quadratic opening downward and l
inear sloping up to the right. They intersect at point negative 2, negative 8 and point 4, 10. Graph of quadratic opening upward and linear sloping up to the right. They do not intersect at point. Graph of quadratic opening downward and linear sloping down to the left. They intersect at point negative 0.9, 0.7. Graph of quadratic opening downward and linear sloping up to the right. They intersect at point negative 1.3, negative 2.2 and point 3.23, 11.73.
1 answer:
The first one. They intersect at (-2,-8) and at (4,10).
You can find this graphically or algebraically.
Graphically by inputting both equations and using the intersect function.
Or algebraically by setting the equation to 0.
Finding the x intercepts then by factoring.
Then inputting the x values into either original equation to find the y intercepts for each.
You can find this graphically or algebraically.
Graphically by inputting both equations and using the intersect function.
Or algebraically by setting the equation to 0.
Finding the x intercepts then by factoring.
Then inputting the x values into either original equation to find the y intercepts for each.
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Hey there :)
- tan²x + sec²x = 1 or 1 + tan²x = sec²x
sin²x + cos²x = 1
Divide the whole by cos²x
so 
and
so 
Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}
1 = - tan²x = sec²x or sec²x - tanx = 1
- tan²x + sec²x = 1 or 1 + tan²x = sec²x
sin²x + cos²x = 1
Divide the whole by cos²x
and
Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}
1 = - tan²x = sec²x or sec²x - tanx = 1