The representation of the genotypes is as follows:
Homozygous dominant for curly hair (James): CC
Heterozygous dominant for curly hair (wife): Cc
The curly or straight hairs are the phenotypes and CC or Cc is the genotype of parental alleles.
When the first child is born which means the F1 generation, the type of hair the child will have can be predicted by punnet squares.
The Punnet squares have been shown in the image.
From the above punnet squares, two out of four probable phenotype or genotype of curly hair is 2/4 = 1/2 or 50%, have CC as their genotype and are homozygous dominant for curly hairs.
The sentences that make sense are "Volatile liquids are flammable" and "Liquids burn easily."
Answer:
50% wild type and 50% black i.e. 1:1 phenotypic ratio
Explanation:
Given, b+ = wild type allele
b = recessive allele
b+b+ = dominant wild type
b+b = heterozygous wild type
bb = recessive black
First cross: female b+b (wild type) X male bb (black) = bb, bb, b+b, b+b
Since bb and b+b are in 1:1 phenotypic ratio, 52 black and 58 wild type progeny are produced.
From this progeny second cross occurs between:
female bb (black) X male (wild type) b+b = bb, bb, b+b, b+b
Again the same 1:1 phenotypic ratio is obtained. Half of the progeny will be be black (bb), other half will be wild type (b+b).
Answer:
3rd
Explanation:
A lysosome is a membrane-bound cell organelle that contains digestive enzymes. Lysosomes are involved with various cell processes. They break down excess or worn-out cell parts. They may be used to destroy invading viruses and bacteria.
I believe the answer to this question is D, I am not sure though.
