Is xylem a internal and external adaptation?

Biology

1 answer:

sergij07 [2.7K]3 years ago

7 0

External adaption because it doesn’t adapt patterns

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During which phase are gametes preparing to divide

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The answer is... Before entering meiosis I, a cell must first go through interphase. This is the same interphase that occurs before mitosis. The cell grows, copies its chromosomes and prepares for division. And to make it more simple the answer is meiosis. Hope this helps!

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A pea plant with the recessive phenotype for plant height would have which of

lilavasa [31]

Answer:

Explanation:

T=dominant

t=recessive

To be considered recessive, 2 lowercase letters are required.

TT or Tt have at least one dominant allele

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What came first, the chicken or the egg? In this scenario, was it reptiles, birds, or dinosaurs? Scientists debate the evolution

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i think the answer is D) but you should get someone else to confirm this.

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A geneticist is studying two genes. each gene can be either dominant or recessive. a sample of 100 individuals is categorized as

Aleksandr-060686 [28]

Attached is a table. I found the exercise on another page on the internet and the sample of 100 individuals was categorised on a table - easier to understand than as it is presented here.
"(a) what is the probability that a random sampled individual, gene 1 is dominant" - We should first add up all of the individuals that are dominant for gene 1 (56+24) and then divide it by the total number of individuals (100).
 $\frac{56+24}{100}$ =0.8
The probability is of 8 in 10 individuals.
"(b) what is the probability that a random sampled individual, gene 2 is dominant" - Follow the same logic as in the previous question.
 $\frac{56+14}{100}$ =0.7
The probability is of 7 in 10 individuals.
"(c) given that gene 1 is dominant, what is the probability that gene 2 is dominant" - Because we are considering those that are dominant for gene 1, our total number of individuals is the total individuals that are dominant for gene 1 and not the whole 100. Once we have this restriction, and we want to know the probability that gene 2 is dominant in these individuals, we should also only consider those that are dominant for gene 2.
 $\frac{56}{56+24}$ =0.7
The probability that gene 2 is dominant, given that that gene 1 is dominant, is of 7 in 10 individuals.

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