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Oksana_A [137]
3 years ago
10

Dave bowers collects u.s. gold coins. he has a collection of 44 coins. some are? $10 coins, and the rest are? $20 coins. if the

face value of the coins is ?$620?, how many of each denomination does he? have
Mathematics
1 answer:
Nataliya [291]3 years ago
8 0
Let x = number of $10 coins.
The total number of coins is 44, therefore there are (44-x) $20 coins.
Total value:
10x + 20(44-x) = 620
-10x + 880 = 620
-10x = -260
x = 26   (number of $10 coins)
44-x = 44-26 = 18 (number of $20 cons)
Answer:
26 $10 coins
18 $20 coins
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Answer: 90% confidence interval for population mean =(21.163, 24.837)

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Step-by-step explanation:

Confidence interval for population mean (\mu) is given by :-

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Given : n= 36 ,  \overline{x}=23 cubic centimeters per cubic meter.

\sigma=6.7cubic centimeters per cubic meter

For 90% confidence level , z= 1.645 [by z-table]

Then, required interval for population mean (\mu) would be :

23\pm (1.645) \dfrac{6.7}{\sqrt{36}}

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=(23-1.837 , 23+ 1.837)=(21.163, 24.837)

For 95% confidence level , z= 1.96 [by z-table]

Then, required interval for population mean (\mu) would be :

23\pm (1.96) \dfrac{6.7}{\sqrt{36}}

=23\pm 2.189

=(23-2.189 , 23+ 2.189)=(20.811, 25.189)

Hence, 90% confidence interval for population mean =(21.163, 24.837)

95% confidence interval for population mean =(20.811, 25.189)

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Hope I helped!

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2%7D-1%7D%7B2-5a%7D%20times%20%5Cfrac%7B15a-6%7D%7Ba%5E%7B2%7D%2B5a-6%7D" id=
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