100-99=1+98=99-97=2+96=98-95=3
2-1=1
the equation is made and the included values are indicated.
"Increased" means to add.
"Quotient" is a total of a division problem.
"A number" means the unknown.
This is our problem: 3 + 6 / N
P(most favorable outcome) = 1 -(0.03 +0.16 -0.01) = 0.82
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"repair fails" includes the "infection and failure" case, as does "infection". By adding the probability of "repair fails" and "infection", we count the "infection and failure" case twice. So, we have to subtract the probability of "infection and failure" from the sum of "repaire fails" and "infection" in order to count each bad outcome only once.
The probability of a good outcome is the complement of the probability of a bad outcome.
Answer:
4/3
Step-by-step explanation:
The tangent of any angle (θ) in standard position that has point (x, y) on its terminal ray is ...
tan(θ) = y/x
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For the given point on the terminal side, the tangent is ...
tan(θ) = (-4)/(-3) = 4/3
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<em>Additional comment</em>
There are several ways this can be explained. One of them makes use of the relation between rectangular and polar coordinates:
(x, y) = (r·cos(θ), r·sin(θ))
Then the ratio y/x is ...
y/x = (r·sin(θ))/(r·cos(θ)) = sin(θ)/cos(θ) = tan(θ)