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Mama L [17]
3 years ago
9

What is the standard form of this equation of a circle? x2 + y2 + 14x - 4y - 28 = 0

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0

We complete the square.

x^2 + y^2 + 14x - 4y - 28 = 0

x^2+14x + y^2 - 4y = 28

x^2+14x + (14/2)^2 + y^2 - 4y + (4/2)^2 = 28 + 49 + 4 = 81

So the answer is:

(x+7)^2 + (y-2)^2 = 9^2

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The terminal side of an angle in standard position passes through p(–3, –4). what is the value of tangent theta?
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Step-by-step explanation:

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<em>Additional comment</em>

There are several ways this can be explained. One of them makes use of the relation between rectangular and polar coordinates:

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