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GarryVolchara [31]
3 years ago
14

What is the solution to your system of linear equations graphed here

Mathematics
1 answer:
Montano1993 [528]3 years ago
4 0
The answer is B. (1,-1). You go one to the right for x, which is positive and down one for y which is negative. Hope this helps!
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If we transform y=x^2 by 5 units to the left and 8 units ups, what is the vertex of the resulting parabola?
sertanlavr [38]

Answer: y = (x + 5)² + 8

<u>Step-by-step explanation:</u>

y = x²

left 5 units:       y = (x + 5)²

up 8 units:        y = (x + 5)² + 8

7 0
3 years ago
Read 2 more answers
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Margaret [11]
Oh gosh, that is so cool
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3 years ago
Does this graph represent a function? Why or why not?
Morgarella [4.7K]

Answer:

Option D is the correct answer

Step-by-step explanation:

D. Yes, because it passes the vertical line test.

7 0
2 years ago
(cos2a *cos 4a+ sin 2a*sin 4a)/sin4a
lyudmila [28]

Answer:

Step-by-step explanation:

(cos 4a*cos 2a+sin 4a*sin 2a)/sin 4a

=[cos (4a-2a)]/sin 4a

=(cos 2a)/sin 4a

=(cos 2a) /(2 sin 2a cos 2a)

=1/(2 sin 2a)

=1/2 csc 2a

4 0
3 years ago
Given: 1; -5; -13 ; -23 ; ...<br><br> Derive a formula for the nth term in the pattern.
mylen [45]

Answer:

  f(n) = -n^2 -3n +5

Step-by-step explanation:

Suppose the formula is ...

  f(n) = an^2 +bn +c

Then we have ...

  f(1) = 1 = a(1^2) +b(1) +c

  f(2) = -5 = a(2^2) +b(2) +c

  f(3) = -13 = a(3^2) +b(3) +c

__

Here's a way to solve these equations.

Subtract the first equation from the second:

  -6 = 3a +b . . . . . 4th equation

Subtract the second equation from the third:

  -8 = 5a +b . . . . . 5th equation

Subtract the fourth equation from the fifth:

  -2 = 2a

  a = -1

Then substituting into the 4th equation to find b, we have ...

  -6 = 3(-1) +b

  -3 = b

and ...

  1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation

  5 = c

The formula is ...

  f(n) = -n^2 -3n +5

3 0
3 years ago
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