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4 years ago

The sum of two numbers is 54 . the smaller number is 12 less than the larger number. what are the numbers?

1 answer:

5 0

<span>Let x=one number and x+12= the other number. Together the numbers=54. Set up the equation: x+x+12=54; Combine the variables; 2x+12=54; Subtract 12 from both sides of the equation; 2x=42; Divide both sides of the equation by 2; x=21 is one number and 21+12=33 is the other number. Check: 2(21) +12=54; 42+12=54; 54=54.</span>

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4 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

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3 years ago

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zubka84 [21]

Answer:

$\huge\boxed{Second\ Number = 42}$

Step-by-step explanation:

Let the consecutive even numbers be x,x+2,x+4, x+ 6, x+ 8 and x+10

So, the given condition is:

x+x+2+x+4+x+6+x+8+x+10 = 270

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Subtracting both sides by 30

6x = 270 - 30

6x = 240

Dividing both sides by 6

x = 40

So,

First Number = x = 40

Second Number = x+2 = 40+2 = 42

Third Number = x+4 = 40+4 = 44

Fourth Number = x+6 = 40+6 = 46

Fifth Number = x+8 = 40+8 = 48

Sixth Number = x+10 = 40+10 = 50

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