Question

What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?

Answer 1

Geometric is
$a_n=a_1r^{n-1}$
an=nth term
a1=first term
r=common ratio
n=which term

commmon ratio is like
a1 times r=a2
4 to 8
4 times 2=8
r=2
first term is 4
therefor

$a_n=4(2)^{n-1}$
the nth term is $4(2)^{n-1}$