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3 years ago

What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?

1 answer:

3 0

Geometric is
$a_n=a_1r^{n-1}$
an=nth term
a1=first term
r=common ratio
n=which term

commmon ratio is like
a1 times r=a2
4 to 8
4 times 2=8
r=2
first term is 4
therefor

$a_n=4(2)^{n-1}$
the nth term is $4(2)^{n-1}$

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Find the period of an electromagnetic wave of wavelength 2.20 × 10–2 m. A. 1.36 × 1010 s c. 7.33 × 10–11 s b. 4.54 × 101 s d. 6.

vovangra [49]

Answer:

7.33 * 10^-11 s

Step-by-step explanation:

Period, T = 1 / f

c = fλ

λ = 2.20 × 10^–2 m

c = speed of light = 3 * 10^8 m

f = c / λ

f = 3 * 10^8 ÷ 2.20 × 10^–2 m

f = (3/2.2) * 10^(8-(-2))

f = 1.364 * 10^10

T = 1/f

T = 1 / 1.364 * 10^10

T = 7.33 * 10^-11 s

4 0

2 years ago

Express the series using sigma notation. 10 + 50 + 250 + 1250.

miskamm [114]

Each next term is being multiplied by 5. Assuming there are only 4 terms to the sum, you have

$10+50+250+1250=10\times5^0+10\times5^1+10\times5^2+10\times5^3=\displaystyle\sum_{i=0}^310\times5^i$

8 0

3 years ago

What's -2x-8y=12 in y intercept form

Free_Kalibri [48]

Y=2/-8x-1.5 ( pretty much add 2x to both sides, then divide all parts by negative 8. So it'd be 2 over -8 and then 12 divided by -8 which equals -1.5)

7 0

2 years ago

What is the greatest common factor of 9x^{2}y9x 2 y and 5x^{4}y^{2}5x 4 y 2 ?

Musya8 [376]

ANSWER

The greatest common factor is
${x}^{2} y$

EXPLANATION

We want to find the greatest common factor of

$9 {x}^{2} y$

and

$5 {x}^{4} {y}^{2}$

The prime factorizations are;

$9 {x}^{2} y = {3}^{2} \times {x}^{2} \times y$

and

$5 {x}^{4} {y}^{2} = 5 \times {x}^{4} \times {y}^{2}$

The product of the least powers of the common factors is the greatest common factor.

$= {x}^{2} y$

7 0

3 years ago

2x + 9 = 23 solve by trial

Allisa [31]

Answer:

i tried it by trial and error, and my work is below.

Step-by-step explanation:

2x + 9 = 23

subtract 9 from both sides

2x = 14

guess.... lol

x=7

8 0

2 years ago