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Arte-miy333 [17]
3 years ago
13

Determine the center and radius of the following circle equation:

Mathematics
1 answer:
-BARSIC- [3]3 years ago
7 0

Answer:

(6, 9 ) and r = 3

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² - 12x - 18y + 108 = 0

Rearrange the x- terms and the y- terms together and subtract 108 from both sides, that is

x² - 12x + y² - 18y = - 108

To obtain standard form use the method of completing the square

add ( half the coefficient of the x and y terms )² to both sides

x² + 2(- 6)x + 36 + y² + 2(- 9)y + 81 = - 108 + 36 + 81

(x - 6)² + (y - 9)² = 9 ← in standard form

with centre = (6, 9 ) and r = \sqrt{9} = 3

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Jaime wants to display her math test scores by using either a line plot or a stem and leaf plot. Her test scores are:
NeX [460]

Answer:

A

Step-by-step explanation:

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6 0
3 years ago
Simplify 3/5 • 3/4 .
Ostrovityanka [42]

Answer:

9/20 as a faction as a decimal 0.45

Step-by-step explanation:

Simplify 3/5 • 3/4

I hope this help

4 0
3 years ago
How can Kendra determine if the function is actually linear?
pashok25 [27]

Answer:

D. She can check to see if the rate of change between the first two ordered pairs is the same as the rate of change between the first and last ordered pairs.

Step-by-step explanation:

Find the rate of change between first two ordered pairs and the second two ordered pairs:

1. Points (2,4) and (3,9). Rate of change:

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{9-4}{3-2}=\dfrac{5}{1}=5

2. Points (3,9) and (4,16). Rate of change:

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{16-9}{4-3}=\dfrac{7}{1}=7

The rate of change for the linear function must the same for each two points on the graph of the function. In this case, the reate of change differs, so this function is not linear and correct option is D.

8 0
3 years ago
Read 2 more answers
A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t
Sati [7]

Answer:

\frac{2}{7}

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = \frac{1}{7}

Remaining fuel after driving around the city = 1 - \frac{1}{7}

                                                                         =    \frac{7 - 1}{7}  = \frac{6}{7}

According to question:

As from the rest of the gas in the car that is \frac{6}{7}, the car can complete 3 trip to Ottawa  which means,

By unitary method:

The car can complete 3 trip by using = \frac{6}{7} tank of gas.

The car can complete 1 trip by using =  \frac{6}{7} \div 3

                                                             =\frac{6}{7} \times\frac{1}{3}

                                                             =  \frac{6}{21}

                                                             = \frac{2}{7} tank of gas

Thus, \frac{2}{7} tank of gas used for each complete trip to Ottawa.

5 0
3 years ago
Trigonometry please help! work need to be shown
padilas [110]

Answer:

x = 5.56

Step-by-step explanation:

Apply trigonometric function to find x

Reference angle = 46°

Hypotenuse = 8

Adjacent length = x

Apply CAH:

Cos 46 = Adj/Hyp

Cos 46 = x/8

8 × Cos 46 = x

5.55726696 = x

x = 5.56 (nearest hundredth)

7 0
3 years ago
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