Answer:
- 16 acres of barley only (no acres of wheat)
Step-by-step explanation:
A graph shows cost of planting puts an upper limit on planted area. The lower limit is provided by the requirement to plant at least 15 acres. The vertices of the feasible solution region are ...
(wheat acres, barley acres) = {(0, 15), (0, 16), (3, 12)}
The profit associated with these scenarios will be ...
for (0, 16): 16·350 = 5600
for (3, 12): 3·450 +12·350 = 1350 +4200 = 5550
To maximize profit, the farmer should plant 16 acres of barley.
A. 8.53 units is the length of the straight which is perpendicular to the straight line CD
Answer:
y=-3x+50
Step-by-step explanation:
y=50-3x ,where x is number of days.
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4