Pls see answer below.
Step-by-step explanation:
In this case, our slope is -8. This means that every hour, the storm is getting closer to the town by 8 miles per hour.
Our y-intercept is 200, which means that its' initial position is 200 miles away from the town.
Hope this helped.
7+3=4+6 Both numbers equal 10
Answer:
1. A. 1
2. D. 
Step-by-step explanation:
Properties used:
- Power of a Power Property
- Product Property
- Quotient Property
- Zero Exponent Property
1. First, let's deal with the numerator.
can be turned into
by using the Power of a Power Property.
And then use the Product Property, 
So now, our fraction is this: 
All number over itself in a fraction is equal to 1. But you can also do this the mathmatic way using the Quotient Property:
or
. Which then you plug the numbers in:
. And since we know that in Zero Exponent Property:
, we can see that
. So either way, we get 1.
So the answer is 1, which is A
2. Power of a Power Property: 
So plug the numbers in the property:
= 
Product Property: 
We plug the equation in with
turned into
---

So the answer is
, which is D
I hope this helps!
Please give Brainliest!
Have a great day!
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
we have

The cos(A) is negative, that means that the angle A in the triangle ABC is an obtuse angle and the value of the sin(A) is positive
The angle A lie on the II Quadrant
step 1
Find the measure of angle A

using a calculator

step 2
Find the sin(A)
we know that

substitute the value of cos(A)




step 3
Find tan(A)
we know that

substitute the values

Simplify
