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jeka94
3 years ago
11

This is Daniela’s work to solve the equation 13 x + 42 = 276.

Mathematics
2 answers:
adell [148]3 years ago
6 0

Answer:

I thinks it c not sure

Step-by-step explanation:

hope this helps sorry if I'm wrong

Yuliya22 [10]3 years ago
4 0
Answer:
Subtraction property of equality.
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How to do the monomials
Cerrena [4.2K]

<u>Given</u>:

The given monomial expression is \frac{16 y^{8}}{4 y^{2}}

We need to simplify the given monomial expression.

<u>Simplification:</u>

Let us simplify the given expression.

Dividing the numbers 16 and 4, we get;

\frac{4 y^{8}}{y^{2}}

Let us apply the exponent rule  \frac{x^{a}}{x^{b}}=x^{a-b} in the above expression.

Thus, we get;

4 y^{8-2}

Subtracting the numbers in the numerator of the above expression, we get;

4 y^{6}

Thus, the simplified expression is 4 y^{6}

8 0
3 years ago
I am giving away 10 points to anybody who provides correct answers with explanations.
QveST [7]

Answer:

5)\ f(n) = 4v

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3 years ago
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Lisa walks from her bus stop to Matt's house, and they walk together to the bus stop. Then, Lisa and Matt take the bus to school
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3 years ago
What is the minimum number of bits required to store each binary string of length 50? (b) what is the minimum number of bits req
antiseptic1488 [7]
In order to answer the above question, you should know the general rule to solve these questions.
The general rule states that there are 2ⁿ subsets of a set with n number of elements and we can use the logarithmic function to get the required number of bits.
That is: 
log₂(2ⁿ) = n number of <span>bits
</span>
a). <span>What is the minimum number of bits required to store each binary string of length 50?
</span>
Answer: In this situation, we have n = 50. Therefore,  2⁵⁰ binary strings of length 50 are there and so it would require:

                                                     log₂(2⁵⁰) <span>= 50 bits.

b). </span><span>what is the minimum number of bits required to store each number with 9 base of ten digits?
</span>
Answer: In this situation, we have n = 50. Therefore, 10⁹ numbers with 9 base ten digits are there and so it would require:

                                                     log2(109)= 29.89 
<span>                                                                     = 30 bits. (rounded to the nearest                                                                                                                        whole #)

c).  </span><span>what is the minimum number of bits required to store each length 10 fixed-density binary string with 4 ones?
</span>
Answer: There is (10,4) length 10 fixed density binary strings with 4 ones and
so it would require:
                                                     log₂(10,4)=log₂(210) = 7.7
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4 0
3 years ago
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