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jeka94
3 years ago
11

This is Daniela’s work to solve the equation 13 x + 42 = 276.

Mathematics
2 answers:
adell [148]3 years ago
6 0

Answer:

I thinks it c not sure

Step-by-step explanation:

hope this helps sorry if I'm wrong

Yuliya22 [10]3 years ago
4 0
Answer:
Subtraction property of equality.
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What is the value of ma-2m+ na for m--2 and n-4?
victus00 [196]
The answer is 2a+4


-2a -2(-2) +4a
-2a +4 +4a
-2a
=2a +4
3 0
3 years ago
(8 x 1,000) + (6 x 100) + (2 x 10) + (4 x 1) +<br> (3 x 100)<br> as a decimal number.
Deffense [45]

Answer:

I believe its 8624.03

Step-by-step explanation:

:)

4 0
3 years ago
15 POINTSSSS‼️‼️
Olenka [21]

Answer:

If the company produce and sell 'x' no. of thing-a-ma-bob , then

C(x) = $ (8809 + 2.05x)

R(x) = $ 4.92x

To make a profit the company must produce and sell at least 3070 thing-a-ma-bobs.

Step-by-step explanation:

If the company produces and sells "x" no. of thing-a-ma-bob, then,

the cost function is given by,

C(x) = $ (8809 + 2.05x) ------------------------(1)

The revenue function is given by,

R(x) = $ 4.92x -------------------------------------(2)

If C(x) = R(x), then,

4.92x = 8809 + 2.05x

⇒ 2.87x = 8809

⇒ x = \frac {8809}{2.87}

⇒ x \simeq 3069.34

So, to make a profit the company must produce and sell at least 3070 thing-a-ma-bobs.

6 0
4 years ago
How much would you need to deposit each month, if you were saving for a down payment on a car that you planned on buying in a ye
Scrat [10]

Answer:

139 dollars a month.

6 0
3 years ago
Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours
s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

cos(x) = \frac{adjacent}{hypotenuse}

cos(47) = \frac{22miles}{hypotenuse} .... flip both fractions.

\frac{1}{cos(47)} = \frac{hypotenuse}{22miles} .... multiply both sides by 22

\frac{22mi}{cos(47)} = hypotenuse

32.26mi = hypotenuse = B

So the distance of ship B from the Harbor is 32.26 miles

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0
3 years ago
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