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lisov135 [29]
4 years ago
15

You are getting a line-up ready for a school kickball game. you have 55 girls and 55 boys. the rules state each child must kick

the same number of times and alternate girl-boy or boy-girl. how many ways can a line-up be made for one round of kicking
Mathematics
1 answer:
marusya05 [52]4 years ago
8 0

To solve this problem, we must first imagine out that the sequence of the children is either <span>
GBGBGB.... or BGBGBG....</span>

So there are 2 possible sequence all in all. Now to solve for the total arrangements per sequence,<span> the girls can be arranged in n! ways in their alloted spots, and so can the boys n! in their alternate spots, therefore:
Total arrangements = 2 * n! * n!</span>

 

If n = 55

Total arrangements = 2 * 55! * 55!

Total arrangements = (The answer is very big ~almost infinite)

 

If n = 5

Total arrangements = 2 * 5! * 5!

Total arrangements = 28,800

 

<span>So I believe the correct given is 5 boys and 5 girls and there are a total of 28,800 arrangements.</span>

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Answer:

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Step-by-step explanation:

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(-13+8)^2 +(4-4)^2 = 25 =r^2

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